O tla tlhatlha ditlhogo tsa mabotlolo di le tharo tsa mebala e e farologaneng sk. Kgetisi ya polasetiki e go sa bonaleng. Di tsenye mo kgetisaneng e go sa bonaleng. Thala objekle e le nngwe o sa lebe mo leng. Kwala maduo a gago mo theiboleng o dirisa tlhal.

Number of green bottle tops = 2
Total number of bottle tops = 10

Probability of picking a green bottle top = $\frac{\text{Number of green bottle tops}}{\text{Total number of bottle tops}}$

The probability is $\frac{1}{5}$. This means it is possible but not certain to pick a green bottle top.

Number of blue bottle tops = 0 (there are no blue bottle tops in the image)
Total number of bottle tops = 10

Probability of picking a blue bottle top = $\frac{\text{Number of blue bottle tops}}{\text{Total number of bottle tops}}$

The probability is 0. This means it is impossible to pick a blue bottle top.

c) The question asks which color bottle tops are most likely to be picked if you pick one 10 times, and it's equally likely to pick any bottle top. The student's work shows "Ke 4 + 4 + 2 = 10". This seems to be an attempt to redistribute the colors. However, the question asks which existing color is most likely.

Yellow: 2
Red: 6
Green: 2

Red has 6 bottle tops, which is more than yellow (2) or green (2).
Therefore, red bottle tops are the most likely to be picked.

Yellow: 2
Red: 6
Green: 2

Red : Green.

The ratio of yellow to red to green bottle tops is $\boxed{\text{1 : 3 : 1}}$.