One number is 2/5 times another number. Their sum is 98. Find the numbers.

Let the two numbers be $x$ and $y$.
According to the problem, one number is $\frac{2}{5}$ times the other. So, we can write:

$$x = \frac{2}{5}y \quad \text{(Equation 1)}$$

The sum of the two numbers is 98:

$$x + y = 98 \quad \text{(Equation 2)}$$

Substitute the expression for $x$ from Equation 1 into Equation 2:

$$\frac{2}{5}y + y = 98$$

Combine the terms involving $y$:

$$\frac{2}{5}y + \frac{5}{5}y = 98$$ $$\frac{2+5}{5}y = 98$$ $$\frac{7}{5}y = 98$$

Multiply both sides by $\frac{5}{7}$:

$$y = 98 \times \frac{5}{7}$$ $$y = \frac{98}{7} \times 5$$ $$y = 14 \times 5$$ $$y = 70$$

Substitute the value of $y$ back into Equation 1:

$$x = \frac{2}{5} \times 70$$ $$x = 2 \times \frac{70}{5}$$ $$x = 2 \times 14$$ $$x = 28$$

The two numbers are 28 and 70.

The two numbers are $\text{28 and 70}$.