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Order these amounts of time in descending order: A) half a week, B) 255,600 seconds, C) 3 days and 14 hours, D) 4740 minutes, E) 82 hours, F) noon on April 27th until noon on May 1st.

Mathematics

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Answers

2 parts
a

1096 days1096 \text{ days}

b

1155 days1155 \text{ days}

Step-by-step solution

5 steps

Here are the solutions to the questions.

2) Order these amounts of time in descending order.

Step 1: Convert all given times into minutes for easy comparison.

  • A: half a week 12 week=3.5 days\frac{1}{2} \text{ week} = 3.5 \text{ days} 3.5 days×24 hours/day=84 hours3.5 \text{ days} \times 24 \text{ hours/day} = 84 \text{ hours} 84 hours×60 minutes/hour=5040 minutes84 \text{ hours} \times 60 \text{ minutes/hour} = 5040 \text{ minutes}
  • B: 255 600 seconds 255600 seconds÷60 seconds/minute=4260 minutes255600 \text{ seconds} \div 60 \text{ seconds/minute} = 4260 \text{ minutes}
  • C: 3 days and 14 hours 3 days×24 hours/day=72 hours3 \text{ days} \times 24 \text{ hours/day} = 72 \text{ hours} 72 hours+14 hours=86 hours72 \text{ hours} + 14 \text{ hours} = 86 \text{ hours} 86 hours×60 minutes/hour=5160 minutes86 \text{ hours} \times 60 \text{ minutes/hour} = 5160 \text{ minutes}
  • D: 4740 minutes Already in minutes: 4740 minutes4740 \text{ minutes}
  • E: 82 hours 82 hours×60 minutes/hour=4920 minutes82 \text{ hours} \times 60 \text{ minutes/hour} = 4920 \text{ minutes}
  • F: noon on April 27th until noon on May 1st This period is exactly 4 days (April 27th to 28th, 28th to 29th, 29th to 30th, 30th to May 1st). 4 days×24 hours/day=96 hours4 \text{ days} \times 24 \text{ hours/day} = 96 \text{ hours} 96 hours×60 minutes/hour=5760 minutes96 \text{ hours} \times 60 \text{ minutes/hour} = 5760 \text{ minutes}

Step 2: List the times in minutes and order them in descending order (longest to shortest).

  • F: 5760 minutes
  • C: 5160 minutes
  • A: 5040 minutes
  • E: 4920 minutes
  • D: 4740 minutes
  • B: 4260 minutes

The descending order is: F, C, A, E, D, B\boxed{\text{F, C, A, E, D, B}}

3) Felix uses a maths learning app daily and has an impressive daily streak.

Part a· 3 steps

What is his daily streak if he has used it every day for exactly 3 years and one of those years was a leap year?

  1. Calculate the number of days for the normal years.

    There are 3 years in total, and one was a leap year, so there are 3−1=23 - 1 = 2 normal years.

    2 normal years×365 days/year=730 days2 \text{ normal years} \times 365 \text{ days/year} = 730 \text{ days}
  2. Calculate the number of days for the leap year.

    1 leap year=366 days1 \text{ leap year} = 366 \text{ days}
  3. Calculate the total daily streak.

    Total streak=730 days+366 days=1096 days\text{Total streak} = 730 \text{ days} + 366 \text{ days} = 1096 \text{ days}

    His daily streak is 1096 days\boxed{1096 \text{ days}}.

Part b

1155 days1155 \text{ days}

If he continues to use it every day for another 2 months, starting on 1st January until the end of February, what will his new daily streak be?

  1. Determine the number of additional days for January and February.

    January has 31 days.
    February has 28 days (assuming it is not a leap year for this additional period, as no specific information is provided).

    Additional days=31 days (January)+28 days (February)=59 days\text{Additional days} = 31 \text{ days (January)} + 28 \text{ days (February)} = 59 \text{ days}
  2. Add the additional days to the streak from part 3a.

    New daily streak=1096 days+59 days=1155 days\text{New daily streak} = 1096 \text{ days} + 59 \text{ days} = 1155 \text{ days}

    His new daily streak will be 1155 days\boxed{1155 \text{ days}}.

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