This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Here are the solutions to the questions:
6.1 Calculate the coordinates of P.
Step 1: P is the y-intercept of the line SP. To find the y-intercept, set in the equation . Step 2: Since , we can divide by . The coordinates of P are .
6.2 Calculate the value of a.
Step 1: S is the x-intercept of the line SP. To find the x-intercept, set in the equation . So, the coordinates of S are .
Step 2: We are given the relation . The length is the distance from the origin to , which is (since ). The length is the distance from the origin to , which is . Substitute these values into the relation: The value of is .
6.3 Determine the equation of RT in the form if it is given that .
Step 1: First, find the gradient of line PS (which is the same as SP). Using , the equation of SP is . Rearrange the equation to the form : The gradient of PS is .
Step 2: We are given that . For perpendicular lines, the product of their gradients is -1.
Step 3: The line RT cuts the y-axis at . This means the y-intercept for line RT is . Substitute the gradient and the y-intercept into . The equation of RT is .
6.4 Calculate the coordinates of R, the point where PS and TR meet.
Step 1: R is the intersection point of line PS and line RT. We have their equations: Line PS: Line RT: Set the values equal to find the -coordinate of R:
Step 2: Multiply the entire equation by 3 to eliminate fractions:
Step 3: Substitute the value of into either equation to find the -coordinate. Using : Find a common denominator, which is 15: The coordinates of R are .
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6.1 Calculate the coordinates of P. Step 1: P is the y-intercept of the line SP.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.