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Perform polynomial long division of the numerator by the denominator.

Mathematics

ScanSolve AI Answer

Answer

2x+xx2−12x + \frac{x}{x^2 - 1}

Step-by-step solution

3 steps
  1. Perform polynomial long division of the numerator by the denominator.

    We want to divide 2x3−x2x^3 - x by x2−1x^2 - 1.

    \multicolumn2r2x\cline2−5x2−12x3+0x2−x\multicolumn2r−(2x3−2x)\cline2−4\multicolumn2r0x\begin{array}{c|cc cc} \multicolumn{2}{r}{2x} \\ \cline{2-5} x^2 - 1 & 2x^3 & +0x^2 & -x \\ \multicolumn{2}{r}{-(2x^3} & & -2x) \\ \cline{2-4} \multicolumn{2}{r}{0} & & x \\ \end{array}

    The quotient is 2x2x and the remainder is xx.

  2. Write the function in the form of quotient plus remainder over divisor.

    This means f(x)=quotient+remainderdivisorf(x) = \text{quotient} + \frac{\text{remainder}}{\text{divisor}}.

    f(x)=2x+xx2−1f(x) = 2x + \frac{x}{x^2 - 1}
  3. Identify g(x)g(x) and h(x)h(x).

    Comparing this to the form g(x)+h(x)g(x) + h(x), we have:
    g(x)=2xg(x) = 2x
    h(x)=xx2−1h(x) = \frac{x}{x^2 - 1}

    The function f(x)f(x) expressed in the form g(x)+h(x)g(x) + h(x) is:

    2x+xx2−12x + \frac{x}{x^2 - 1}
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