We read your photo as:

Place the compass needle at point X and open the compass to a radius greater than half the length of side XY.

Mathematics

ScanSolve AI Answer

Step-by-step solution

8 steps

Here are the instructions for parts b, c, and d, continuing from your previous construction of triangle XYZ.

Part b· 4 steps

To construct the perpendicular bisector of side XY

  1. Place the compass needle at point X and open the compass to a radius greater than half the length of side XY.

  2. Draw an arc above and below the line segment XY.

  3. Without changing the compass opening, place the compass needle at point Y and draw another set of arcs above and below XY, ensuring they intersect the first set of arcs.

  4. Draw a straight line connecting the two points where the arcs intersect.

    This line is the perpendicular bisector of side XY.

Part c· 4 steps

To construct the perpendicular bisector of side XZ

  1. Place the compass needle at point X and open the compass to a radius greater than half the length of side XZ.

  2. Draw an arc above and below the line segment XZ.

  3. Without changing the compass opening, place the compass needle at point Z and draw another set of arcs above and below XZ, ensuring they intersect the first set of arcs.

  4. Draw a straight line connecting the two points where the arcs intersect.

    This line is the perpendicular bisector of side XZ.

Part d

What do you notice?

You will notice that the perpendicular bisector of the base XZ passes through the vertex Y. Also, the perpendicular bisectors of all three sides (XY, YZ, and XZ) will intersect at a single point, which is the circumcenter of the triangle.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp