Find the prime factors of 244036 and 103823. Hence, evaluate sqrt(244036)/cbrt(103823).

$$244036 \div 2 = 122018$$ $$122018 \div 2 = 61009$$

61009 haigawanyiki kwa 3, 5, 7, 11. Jaribu 13.

$$61009 \div 13 = 4693$$ $$4693 \div 13 = 361$$

361 ni mraba wa 19.

$$361 \div 19 = 19$$ $$19 \div 19 = 1$$

Hivyo, vigawo vikuu vya 244036 ni $2 \times 2 \times 13 \times 13 \times 19 \times 19$.
Katika fomu ya vipeo: $244036 = 2^2 \times 13^2 \times 19^2$.

Kwa 103823:

103823 haigawanyiki kwa 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43. Jaribu 47.

$$103823 \div 47 = 2209$$

2209 ni mraba wa 47.

$$2209 \div 47 = 47$$ $$47 \div 47 = 1$$

Hivyo, vigawo vikuu vya 103823 ni $47 \times 47 \times 47$.
Katika fomu ya vipeo: $103823 = 47^3$.

Vigawo vikuu ni:
$244036 = \boxed{2^2 \times 13^2 \times 19^2}$
$103823 = \boxed{47^3}$

Kutoka sehemu (a), $244036 = 2^2 \times 13^2 \times 19^2$.

$$\sqrt{244036} = \sqrt{2^2 \times 13^2 \times 19^2}$$ $$\sqrt{244036} = 2 \times 13 \times 19$$ $$\sqrt{244036} = 26 \times 19$$ $$\sqrt{244036} = 494$$

Kutoka sehemu (a), $103823 = 47^3$.

$$\sqrt[3]{103823} = \sqrt[3]{47^3}$$ $$\sqrt[3]{103823} = 47$$

$$\frac{\sqrt{244036}}{\sqrt[3]{103823}} = \frac{494}{47}$$ $$\frac{494}{47} = 10.510638...$$

Kama sehemu, jibu ni $\frac{494}{47}$.

Thamani ya usemi ni $\boxed{\frac{494}{47}}$.