Find the radius

Mathematics

ScanSolve AI Answer

Answer

5 cm5\, \text{cm}

Step-by-step solution

4 steps
  1. Identify the properties of the given figure.

    The line segment AB is tangent to the circle at point A.
    The line segment OA is the radius of the circle to the point of tangency.
    A fundamental property of circles is that the radius drawn to the point of tangency is perpendicular to the tangent line.
    Therefore, ∠OAB=90∘\angle OAB = 90^\circ.
    This means that △OAB\triangle OAB is a right-angled triangle with the right angle at A.

  2. Apply the Pythagorean theorem.

    In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
    In △OAB\triangle OAB:

    • Hypotenuse = OB = 13 cm
    • One leg = AB = 12 cm
    • Other leg = OA = r (the radius)

    According to the Pythagorean theorem:

    OA2+AB2=OB2OA^2 + AB^2 = OB^2
  3. Substitute the given values into the equation.

    r2+(12 cm)2=(13 cm)2r^2 + (12\, \text{cm})^2 = (13\, \text{cm})^2
  4. Solve for rr.

    r2+144 cm2=169 cm2r^2 + 144\, \text{cm}^2 = 169\, \text{cm}^2

    Subtract 144 cm2144\, \text{cm}^2 from both sides:

    r2=169 cm2−144 cm2r^2 = 169\, \text{cm}^2 - 144\, \text{cm}^2 r2=25 cm2r^2 = 25\, \text{cm}^2

    Take the square root of both sides:

    r=25 cm2r = \sqrt{25\, \text{cm}^2} r=5 cmr = 5\, \text{cm}

    The radius is 5 cm5\, \text{cm}.

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