Determine the ratio of the original price to the reduced price.

The price of rice decreases by 24%.
Let the original price be $P_0$. The reduced price $P_1$ is $P_0 - 0.24 P_0 = 0.76 P_0$.
The ratio of original price to reduced price is $P_0 : P_1 = 1 : 0.76$.
To work with whole numbers, we can consider the original price as 100 units.
Original price: 100 units
Reduced price: $100 - 24 = 76$ units
The ratio of original price to reduced price is $100:76$.
Simplifying this ratio by dividing both sides by 4:

$$P_0 : P_1 = \frac{100}{4} : \frac{76}{4} = 25 : 19$$

For a fixed expenditure (₹2,500), the quantity of rice that can be bought is inversely proportional to its price.
So, if $P_0 : P_1 = 25 : 19$, then the ratio of the original quantity ($Q_0$) to the new quantity ($Q_1$) is:

$$Q_0 : Q_1 = 19 : 25$$

The problem states that Alok can buy 10 kg more rice. This means the difference between the new quantity and the original quantity is 10 kg.
In terms of units from our ratio, the increase in quantity is $25 - 19 = 6$ units.
We are given that 6 units correspond to 10 kg.

$$6 \text{ units} = 10 \text{ kg}$$

To find the new quantity ($Q_1$), which is 25 units:

$$1 \text{ unit} = \frac{10}{6} \text{ kg} = \frac{5}{3} \text{ kg}$$ $$Q_1 = 25 \text{ units} = 25 \times \frac{5}{3} \text{ kg} = \frac{125}{3} \text{ kg}$$

So, Alok buys $\frac{125}{3}$ kg of rice at the reduced price.

The total expenditure is ₹2,500.
The new quantity of rice is $\frac{125}{3}$ kg.
The reduced price per kg is the total expenditure divided by the new quantity:

$$\text{Reduced price per kg} = \frac{\text{Total Expenditure}}{\text{New Quantity}}$$ $$\text{Reduced price per kg} = \frac{₹2500}{\frac{125}{3} \text{ kg}}$$ $$\text{Reduced price per kg} = \frac{2500 \times 3}{125} \text{ ₹/kg}$$ $$\text{Reduced price per kg} = \frac{7500}{125} \text{ ₹/kg}$$ $$\text{Reduced price per kg} = 60 \text{ ₹/kg}$$

The reduced price per kg is ₹60. This corresponds to option c.

The final answer is $\text{c. ₹60}$.