Refer to the given figure below to answer A8 - A10.

The figure is a quadrilateral TSNE. The arrows on TN and SE indicate that $TN \parallel SE$. The tick marks on TS and NE indicate that $TS = NE$. These properties define the figure as an isosceles trapezoid.

In an isosceles trapezoid, two key properties are:

1. The lengths of the non-parallel sides (legs) are equal: $TS = NE$. Setting the expressions equal: $2x + 3 = x + 12 \implies x = 9$.
2. The consecutive interior angles between the parallel bases and a non-parallel side (leg) are supplementary. For leg NE, $\angle TEN$ and $\angle ENS$ are consecutive interior angles. Setting the sum of the expressions to $180^\circ$: $(5x + 4) + (7x + 8) = 180 \implies 12x + 12 = 180 \implies 12x = 168 \implies x = 14$.

Since these two properties yield different values for $x$ ($x=9$ from side lengths and $x=14$ from angles), there is an inconsistency in the problem statement. We will proceed by using the value of $x$ derived from the angle relationship, as it involves both given angle expressions.

Using $x=14$ from the angle relationship:

$$\angle TEN = (5x + 4)^\circ = (5(14) + 4)^\circ = (70 + 4)^\circ = 74^\circ$$

The measure of $\angle TEN$ is $\boxed{\text{74}^\circ}$.

Using $x=14$:

$$\angle ENS = (7x + 8)^\circ = (7(14) + 8)^\circ = (98 + 8)^\circ = 106^\circ$$

The measure of $\angle ENS$ is $\boxed{\text{106}^\circ}$.
(Check: $74^\circ + 106^\circ = 180^\circ$, which is consistent with the supplementary angle property.)

Using $x=14$:

$$\text{TS} = (2x + 3) \text{ cm} = (2(14) + 3) \text{ cm} = (28 + 3) \text{ cm} = 31 \text{ cm}$$

The length of TS is $\boxed{\text{31 cm}}$.