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Rewrite the first mixed number to allow for subtraction of the fractions.

Mathematics

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2 parts
g

167\mathbf{1\frac{6}{7}}

h

6611\mathbf{6\frac{6}{11}}

Step-by-step solution

7 steps

Here are the solutions for problems g) and h).

Part g· 3 steps

  1. Rewrite the first mixed number to allow for subtraction of the fractions.

    Since 37<47\frac{3}{7} < \frac{4}{7}, we borrow 1 from the whole number 7.

    737=6+1+37=6+77+37=61077\frac{3}{7} = 6 + 1 + \frac{3}{7} = 6 + \frac{7}{7} + \frac{3}{7} = 6\frac{10}{7}
  2. Perform the subtraction using the rewritten mixed number.

    6107−547=(6−5)+(107−47)6\frac{10}{7} - 5\frac{4}{7} = (6-5) + \left(\frac{10}{7} - \frac{4}{7}\right)
  3. Subtract the whole numbers and the fractions.

    1+10−47=1+671 + \frac{10-4}{7} = 1 + \frac{6}{7}

    The difference is 167\boxed{\mathbf{1\frac{6}{7}}}.

Part h

6611\mathbf{6\frac{6}{11}}

  1. Add the first two terms.

    Add the whole numbers and the fractions separately.

    5411+1511=(5+1)+(411+511)5\frac{4}{11} + 1\frac{5}{11} = (5+1) + \left(\frac{4}{11} + \frac{5}{11}\right)
  2. Perform the additions.

    6+911=69116 + \frac{9}{11} = 6\frac{9}{11}
  3. Subtract the last fraction from the result.

    6911−311=6+(911−311)6\frac{9}{11} - \frac{3}{11} = 6 + \left(\frac{9}{11} - \frac{3}{11}\right)
  4. Perform the subtraction of the fractions.

    6+9−311=6+6116 + \frac{9-3}{11} = 6 + \frac{6}{11}

    The result is 6611\boxed{\mathbf{6\frac{6}{11}}}.

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