Round of to the nearest hole number a) 426 56 b) 1009.3 x 1.998 c) 10.5 - 3.4 Write the following numbers in c) 317 x 36 9x x 910 24a7 + 6a3 Simplify by removing fractions d) 81^(1/4) (x3)^(4/3) 9^(1/2) d) (x3)^(1/3)

Question

Asked on June 21, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

Accepted Answer · 2026-06-21T10:47:55.658Z

Haya hapa masuluhisho ya maswali yako: Zungusha nambari zifuatazo hadi nambari kamili iliyo karibu zaidi: a) Step 1: Gawanya nambari. 426 ÷ 11.56 ≈ 36.8512 Step 2: Zungusha hadi nambari kamili iliyo karibu zaidi. Kwa kuwa tarakimu ya kwanza baada ya desimali (8) ni 5 au zaidi, tunazungusha juu. ≈ 37 Jibu: 37 b) Step 1: Zidisha nambari. 1009.3 × 1.998 ≈ 2016.5814 Step 2: Zungusha hadi nambari kamili iliyo karibu zaidi. Kwa kuwa tarakimu ya kwanza baada ya desimali (5) ni 5 au zaidi, tunazungusha juu. ≈ 2017 Jibu: 2017 c) Step 1: Toa nambari. 10.5 - 3.4 = 7.1 Step 2: Zungusha hadi nambari kamili iliyo karibu zaidi. Kwa kuwa tarakimu ya kwanza baada ya desimali (1) ni chini ya 5, tunazungusha chini. ≈ 7 Jibu: 7 Andika nambari zifuatazo katika fomu ya kiashiria (kurahisisha kwa kutumia sheria za viashiria): 3^17 × 3^6 Step 1: Tumia sheria ya viashiria a^m × a^n = a^m+n. 3^17+6 Step 2: Jumlisha viashiria. 3^23 Jibu: 3^23 a^23 × a^10 Step 1: Tumia sheria ya viashiria a^m × a^n = a^m+n. a^23+10 Step 2: Jumlisha viashiria. a^33 Jibu: a^33 24a^7 ÷ 6a^3 Step 1: Gawanya vizidishi na vigezo tofauti. (24)/(6) × (a^7)/(a^3) Step 2: Tumia sheria ya viashiria a^m ÷ a^n = a^m-n. 4 × a^7-3 Step 3: Rahisisha. 4a^4 Jibu: 4a^4 Rahisisha kwa kuondoa sehemu (viashiria vya sehemu): a) 81^(1)/(4) Step 1: Badilisha kiashiria cha sehemu kuwa mzizi. a^(1)/(n) = [n]a. [4]81 Step 2: Tafuta nambari ambayo ikizidishwa yenyewe mara nne inatoa 81. 3^4 = 81 Jibu: 3 (cx^3)^(4)/(3) Step 1: Tumia kiashiria kwa kila neno ndani ya mabano: (ab)^n = a^n b^n. c^(4)/(3) × (x^3)^(4)/(3) Step 2: Tumia sheria ya nguvu ya nguvu: (a^m)^n = a^mn. c^(4)/(3) × x^3 × (4)/(3) Step 3: Rahisisha viashiria. c^(4)/(3) x^4 Step 4: Andika upya c^(4)/(3) kama c^1 + (1)/(3) = c^1 · c^(1)/(3) = c[3]c. c x^4 [3]c Jibu: cx^4[3]c d) 9^(1)/(2) Step 1: Badilisha kiashiria cha sehemu kuwa mzizi. a^(1)/(n) = [n]a. sqrt(9) Step 2: Tafuta mzizi wa mraba wa 9. 3 Jibu: 3 (z^3)^(1)/(3) Step 1: Tumia sheria ya nguvu ya nguvu: (a^m)^n = a^mn. z^3 × (1)/(3) Step 2: Rahisisha kiashiria. z^1 Jibu: z Tuma swali linalofuata 📸

Accepted Answer · 2026-06-21T10:47:55.658Z

Haya hapa masuluhisho ya maswali yako: Zungusha nambari zifuatazo hadi nambari kamili iliyo karibu zaidi: a) Step 1: Gawanya nambari. 426 ÷ 11.56 ≈ 36.8512 Step 2: Zungusha hadi nambari kamili iliyo karibu zaidi. Kwa kuwa tarakimu ya kwanza baada ya desimali (8) ni 5 au zaidi, tunazungusha juu. ≈ 37 Jibu: 37 b) Step 1: Zidisha nambari. 1009.3 × 1.998 ≈ 2016.5814 Step 2: Zungusha hadi nambari kamili iliyo karibu zaidi. Kwa kuwa tarakimu ya kwanza baada ya desimali (5) ni 5 au zaidi, tunazungusha juu. ≈ 2017 Jibu: 2017 c) Step 1: Toa nambari. 10.5 - 3.4 = 7.1 Step 2: Zungusha hadi nambari kamili iliyo karibu zaidi. Kwa kuwa tarakimu ya kwanza baada ya desimali (1) ni chini ya 5, tunazungusha chini. ≈ 7 Jibu: 7 Andika nambari zifuatazo katika fomu ya kiashiria (kurahisisha kwa kutumia sheria za viashiria): 3^17 × 3^6 Step 1: Tumia sheria ya viashiria a^m × a^n = a^m+n. 3^17+6 Step 2: Jumlisha viashiria. 3^23 Jibu: 3^23 a^23 × a^10 Step 1: Tumia sheria ya viashiria a^m × a^n = a^m+n. a^23+10 Step 2: Jumlisha viashiria. a^33 Jibu: a^33 24a^7 ÷ 6a^3 Step 1: Gawanya vizidishi na vigezo tofauti. (24)/(6) × (a^7)/(a^3) Step 2: Tumia sheria ya viashiria a^m ÷ a^n = a^m-n. 4 × a^7-3 Step 3: Rahisisha. 4a^4 Jibu: 4a^4 Rahisisha kwa kuondoa sehemu (viashiria vya sehemu): a) 81^(1)/(4) Step 1: Badilisha kiashiria cha sehemu kuwa mzizi. a^(1)/(n) = [n]a. [4]81 Step 2: Tafuta nambari ambayo ikizidishwa yenyewe mara nne inatoa 81. 3^4 = 81 Jibu: 3 (cx^3)^(4)/(3) Step 1: Tumia kiashiria kwa kila neno ndani ya mabano: (ab)^n = a^n b^n. c^(4)/(3) × (x^3)^(4)/(3) Step 2: Tumia sheria ya nguvu ya nguvu: (a^m)^n = a^mn. c^(4)/(3) × x^3 × (4)/(3) Step 3: Rahisisha viashiria. c^(4)/(3) x^4 Step 4: Andika upya c^(4)/(3) kama c^1 + (1)/(3) = c^1 · c^(1)/(3) = c[3]c. c x^4 [3]c Jibu: cx^4[3]c d) 9^(1)/(2) Step 1: Badilisha kiashiria cha sehemu kuwa mzizi. a^(1)/(n) = [n]a. sqrt(9) Step 2: Tafuta mzizi wa mraba wa 9. 3 Jibu: 3 (z^3)^(1)/(3) Step 1: Tumia sheria ya nguvu ya nguvu: (a^m)^n = a^mn. z^3 × (1)/(3) Step 2: Rahisisha kiashiria. z^1 Jibu: z Tuma swali linalofuata 📸

Round of to the nearest hole number a) 426 56 b) 1009.3 x 1.998 c) 10.5 - 3.4 Write the following numbers in c) 317 x 36 9x x 910 24a7 + 6a3 Simplify by removing fractions d) 81^(1/4) (x3)^(4/3) 9^(1/2) d) (x3)^(1/3)

Need help with your own homework?

More Mathematics Questions

Round of to the nearest hole number a) 426 56 b) 1009.3 x 1.998 c) 10.5 - 3.4 Write the following numbers in c) 317 x 36 9x x 910 24a7 + 6a3 Simplify by removing fractions d) 81^(1/4) (x3)^(4/3) 9^(1/2) d) (x3)^(1/3)

Need help with your own homework?

More Mathematics Questions