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Round of to the nearest hole number a) 426 56 b) 1009.3 x 1.998 c) 10.5 - 3.4 Write the following numbers in c) 317 x 36 9x x 910 24a7 + 6a3 Simplify by removing fractions d) 81^(1/4) (x3)^(4/3) 9^(1/2) d) (x3)^(1/3)

Mathematics

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Haya hapa masuluhisho ya maswali yako:

Zungusha nambari zifuatazo hadi nambari kamili iliyo karibu zaidi:

a)

  1. Gawanya nambari.

    426÷11.56≈36.8512426 \div 11.56 \approx 36.8512
  2. Zungusha hadi nambari kamili iliyo karibu zaidi.

    Kwa kuwa tarakimu ya kwanza baada ya desimali (8) ni 5 au zaidi, tunazungusha juu.

    ≈37\approx 37

    Jibu: 37\boxed{\text{37}}

    b)

  3. Zidisha nambari.

    1009.3×1.998≈2016.58141009.3 \times 1.998 \approx 2016.5814
  4. Zungusha hadi nambari kamili iliyo karibu zaidi.

    Kwa kuwa tarakimu ya kwanza baada ya desimali (5) ni 5 au zaidi, tunazungusha juu.

    ≈2017\approx 2017

    Jibu: 2017\boxed{\text{2017}}

    c)

  5. Toa nambari.

    10.5−3.4=7.110.5 - 3.4 = 7.1
  6. Zungusha hadi nambari kamili iliyo karibu zaidi.

    Kwa kuwa tarakimu ya kwanza baada ya desimali (1) ni chini ya 5, tunazungusha chini.

    ≈7\approx 7

    Jibu: 7\boxed{\text{7}}

    Andika nambari zifuatazo katika fomu ya kiashiria (kurahisisha kwa kutumia sheria za viashiria):

    • 317×363^{17} \times 3^6
  7. Tumia sheria ya viashiria am×an=am+na^m \times a^n = a^{m+n}.

    $$
    3^{17+6}
    $$
    
  8. Jumlisha viashiria.

    $$
    3^{23}
    $$
    Jibu: $\boxed{3^{23}}$
    
    • a23×a10a^{23} \times a^{10}
  9. Tumia sheria ya viashiria am×an=am+na^m \times a^n = a^{m+n}.

    $$
    a^{23+10}
    $$
    
  10. Jumlisha viashiria.

    $$
    a^{33}
    $$
    Jibu: $\boxed{a^{33}}$
    
    • 24a7÷6a324a^7 \div 6a^3
  11. Gawanya vizidishi na vigezo tofauti.

    $$
    \frac{24}{6} \times \frac{a^7}{a^3}
    $$
    
  12. Tumia sheria ya viashiria am÷an=am−na^m \div a^n = a^{m-n}.

    $$
    4 \times a^{7-3}
    $$
    
  13. Rahisisha.

    $$
    4a^4
    $$
    Jibu: $\boxed{4a^4}$
    

    Rahisisha kwa kuondoa sehemu (viashiria vya sehemu):

    a)

    • 811481^{\frac{1}{4}}
  14. Badilisha kiashiria cha sehemu kuwa mzizi.

    a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}. 814 \sqrt[4]{81}

  15. Tafuta nambari ambayo ikizidishwa yenyewe mara nne inatoa 81.

    $$
    3^4 = 81
    $$
    Jibu: $\boxed{3}$
    
    • (cx3)43(cx^3)^{\frac{4}{3}}
  16. Tumia kiashiria kwa kila neno ndani ya mabano

    (ab)n=anbn(ab)^n = a^n b^n. c43×(x3)43 c^{\frac{4}{3}} \times (x^3)^{\frac{4}{3}}

  17. Tumia sheria ya nguvu ya nguvu

    (am)n=amn(a^m)^n = a^{mn}. c43×x3×43 c^{\frac{4}{3}} \times x^{3 \times \frac{4}{3}}

  18. Rahisisha viashiria.

    $$
    c^{\frac{4}{3}} x^4
    $$
    
  19. Andika upya c43c^{\frac{4}{3}} kama c1+13=c1⋅c13=cc3c^{1 + \frac{1}{3}} = c^1 \cdot c^{\frac{1}{3}} = c\sqrt[3]{c}.

    $$
    c x^4 \sqrt[3]{c}
    $$
    Jibu: $\boxed{cx^4\sqrt[3]{c}}$
    

    d)

    • 9129^{\frac{1}{2}}
  20. Badilisha kiashiria cha sehemu kuwa mzizi.

    a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}. 9 \sqrt{9}

  21. Tafuta mzizi wa mraba wa 9.

    $$
    3
    $$
    Jibu: $\boxed{3}$
    
    • (z3)13(z^3)^{\frac{1}{3}}
  22. Tumia sheria ya nguvu ya nguvu

    (am)n=amn(a^m)^n = a^{mn}. z3×13 z^{3 \times \frac{1}{3}}

  23. Rahisisha kiashiria.

    $$
    z^1
    $$
    Jibu: $\boxed{z}$
    
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