✍️ ScanSolve (2/2) · 3/5 today

That's a great solution, David!

✅ Correct.

Your steps correctly identify the standard form of a horizontal parabola, $(y-k)^2 = 4p(x-h)$, where $(h, k)$ is the vertex. By rewriting $y^2 = 8x$ as $(y-0)^2 = 8(x-0)$, you correctly determined that $h=0$ and $k=0$.

The vertex of the parabola is $(0,0)$.