Shade the areas correctly to show the fractions.

Question

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Here are the solutions for the remaining problems:

6.

Find a common denominator for $\frac{7}{10}$ , $\frac{15}{30}$ , and $\frac{3}{20}$ .
The least common multiple of 10, 30, and 20 is 60.
$\frac{7}{10} - \frac{15}{30} + \frac{3}{20} = \frac{7 \times 6}{10 \times 6} - \frac{15 \times 2}{30 \times 2} + \frac{3 \times 3}{20 \times 3}$
Perform the operations.
$= \frac{42}{60} - \frac{30}{60} + \frac{9}{60} = \frac{42 - 30 + 9}{60} = \frac{12 + 9}{60} = \frac{21}{60}$
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 3.
$= \frac{21 \div 3}{60 \div 3} = \frac{7}{20}$
The final answer is $\boxed{\frac{7}{20}}$ .

7.
Find a common denominator for $\frac{5}{14}$ , $\frac{3}{28}$ , and $\frac{3}{4}$ .
The least common multiple of 14, 28, and 4 is 28.
$\frac{5}{14} - \frac{3}{28} + \frac{3}{4} = \frac{5 \times 2}{14 \times 2} - \frac{3}{28} + \frac{3 \times 7}{4 \times 7}$
Perform the operations.
$= \frac{10}{28} - \frac{3}{28} + \frac{21}{28} = \frac{10 - 3 + 21}{28} = \frac{7 + 21}{28} = \frac{28}{28}$
Simplify the fraction.
$= 1$
The final answer is $\boxed{1}$ .

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