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Shashank and Vikas have the same storybook. Shashank has read 2/5 of the book and Vikas has read 7/2 of the book. Who has read more pages?
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93 stepsHere are the solutions to the problems:
1. Compare the fractions without finding the LCM. Put or in the .
- 1(a):
Compare the numerators since the denominators are the same.
$$ 1 < 2 $$Therefore,
$$ \frac{1}{4} < \frac{2}{4} $$ The answer is $\boxed{<}$- 1(b):
Compare the denominators since the numerators are the same.
The fraction with the smaller denominator is larger.
Therefore,
$$ \frac{3}{5} > \frac{3}{7} $$ The answer is $\boxed{>}$- 1(c):
Compare the denominators.
$$ 4 < 8 $$Therefore,
$$ \frac{3}{4} > \frac{3}{8} $$ The answer is $\boxed{>}$- 1(d):
Compare the denominators.
$$ 15 > 12 $$Therefore,
$$ \frac{5}{15} < \frac{5}{12} $$ The answer is $\boxed{<}$- 1(e):
Compare the denominators.
$$ 18 > 12 $$Therefore,
$$ \frac{4}{18} < \frac{4}{12} $$ The answer is $\boxed{<}$- 1(f):
Compare the denominators.
$$ 19 > 10 $$Therefore,
$$ \frac{9}{19} < \frac{9}{10} $$ The answer is $\boxed{<}$- 1(g):
Compare the denominators.
$$ 5 < 10 $$Therefore,
$$ \frac{2}{5} > \frac{2}{10} $$ The answer is $\boxed{>}$- 1(h):
Simplify the second fraction.
$$ \frac{4}{6} = \frac{2}{3} $$Compare the fractions.
$$ \frac{2}{3} = \frac{2}{3} $$ The answer is $\boxed{=}$2. Compare the fractions and put or in the .
- 2(a):
Cross-multiply the fractions.
$$ 3 \times 3 = 9 $$ $$ 4 \times 2 = 8 $$Compare the products.
$$ 9 > 8 $$Therefore,
$$ \frac{3}{4} > \frac{2}{3} $$ The answer is $\boxed{>}$- 2(b):
Cross-multiply the fractions.
$$ 4 \times 4 = 16 $$ $$ 5 \times 3 = 15 $$Compare the products.
$$ 16 > 15 $$Therefore,
$$ \frac{4}{5} > \frac{3}{4} $$ The answer is $\boxed{>}$- 2(c):
Simplify the first fraction.
$$ \frac{2}{10} = \frac{1}{5} $$Cross-multiply and .
$$ 1 \times 4 = 4 $$ $$ 5 \times 3 = 15 $$Compare the products.
$$ 4 < 15 $$Therefore,
$$ \frac{2}{10} < \frac{3}{4} $$ The answer is $\boxed{<}$- 2(d):
Cross-multiply the fractions.
$$ 2 \times 4 = 8 $$ $$ 5 \times 3 = 15 $$Compare the products.
$$ 8 < 15 $$Therefore,
$$ \frac{2}{5} < \frac{3}{4} $$ The answer is $\boxed{<}$- 2(e):
Cross-multiply the fractions.
$$ 4 \times 8 = 32 $$ $$ 9 \times 5 = 45 $$Compare the products.
$$ 32 < 45 $$Therefore,
$$ \frac{4}{9} < \frac{5}{8} $$ The answer is $\boxed{<}$- 2(f):
Simplify both fractions.
$$ \frac{4}{8} = \frac{1}{2} $$ $$ \frac{5}{10} = \frac{1}{2} $$Compare the simplified fractions.
$$ \frac{1}{2} = \frac{1}{2} $$ The answer is $\boxed{=}$- 2(g):
Simplify the second fraction.
$$ \frac{8}{10} = \frac{4}{5} $$Compare the fractions.
$$ \frac{3}{5} < \frac{4}{5} $$Therefore,
$$ \frac{3}{5} < \frac{8}{10} $$ The answer is $\boxed{<}$- 2(h):
Simplify the second fraction.
$$ \frac{2}{8} = \frac{1}{4} $$Convert to an equivalent fraction with denominator 16.
$$ \frac{1}{4} = \frac{1 \times 4}{4 \times 4} = \frac{4}{16} $$Compare and .
$$ 5 > 4 $$Therefore,
$$ \frac{5}{16} > \frac{2}{8} $$ The answer is $\boxed{>}$3. Arrange in ascending order.
- 3(a):
Since the numerators are the same, the fraction with the largest denominator is the smallest.
Arrange in ascending order.
$$ \frac{1}{5} < \frac{1}{4} < \frac{1}{3} $$ The ascending order is $\boxed{\frac{1}{5}, \frac{1}{4}, \frac{1}{3}}$- 3(b):
Find the LCM of the denominators (4, 8, 12), which is 24.
Convert each fraction to an equivalent fraction with denominator 24.
$$ \frac{3}{4} = \frac{3 \times 6}{4 \times 6} = \frac{18}{24} $$ $$ \frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24} $$ $$ \frac{5}{12} = \frac{5 \times 2}{12 \times 2} = \frac{10}{24} $$Arrange the fractions in ascending order based on their numerators.
$$ \frac{9}{24} < \frac{10}{24} < \frac{18}{24} $$Write the original fractions in ascending order.
$$ \frac{3}{8} < \frac{5}{12} < \frac{3}{4} $$ The ascending order is $\boxed{\frac{3}{8}, \frac{5}{12}, \frac{3}{4}}$- 3(c):
Find the LCM of the denominators (2, 3, 4), which is 12.
Convert each fraction to an equivalent fraction with denominator 12.
$$ \frac{1}{2} = \frac{1 \times 6}{2 \times 6} = \frac{6}{12} $$ $$ \frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12} $$ $$ \frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12} $$ $$ \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} $$Arrange the fractions in ascending order.
$$ \frac{4}{12} < \frac{6}{12} < \frac{8}{12} < \frac{9}{12} $$Write the original fractions in ascending order.
$$ \frac{1}{3} < \frac{1}{2} < \frac{2}{3} < \frac{3}{4} $$ The ascending order is $\boxed{\frac{1}{3}, \frac{1}{2}, \frac{2}{3}, \frac{3}{4}}$- 3(d):
Find the LCM of the denominators (18, 9, 3, 2), which is 18.
Convert each fraction to an equivalent fraction with denominator 18.
$$ \frac{11}{18} $$ $$ \frac{5}{9} = \frac{5 \times 2}{9 \times 2} = \frac{10}{18} $$ $$ \frac{2}{3} = \frac{2 \times 6}{3 \times 6} = \frac{12}{18} $$ $$ \frac{1}{2} = \frac{1 \times 9}{2 \times 9} = \frac{9}{18} $$Arrange the fractions in ascending order.
$$ \frac{9}{18} < \frac{10}{18} < \frac{11}{18} < \frac{12}{18} $$Write the original fractions in ascending order.
$$ \frac{1}{2} < \frac{5}{9} < \frac{11}{18} < \frac{2}{3} $$ The ascending order is $\boxed{\frac{1}{2}, \frac{5}{9}, \frac{11}{18}, \frac{2}{3}}$- 3(e):
Find the LCM of the denominators (5, 10, 15, 3), which is 30.
Convert each fraction to an equivalent fraction with denominator 30.
$$ \frac{4}{5} = \frac{4 \times 6}{5 \times 6} = \frac{24}{30} $$ $$ \frac{9}{10} = \frac{9 \times 3}{10 \times 3} = \frac{27}{30} $$ $$ \frac{7}{15} = \frac{7 \times 2}{15 \times 2} = \frac{14}{30} $$ $$ \frac{2}{3} = \frac{2 \times 10}{3 \times 10} = \frac{20}{30} $$Arrange the fractions in ascending order.
$$ \frac{14}{30} < \frac{20}{30} < \frac{24}{30} < \frac{27}{30} $$Write the original fractions in ascending order.
$$ \frac{7}{15} < \frac{2}{3} < \frac{4}{5} < \frac{9}{10} $$ The ascending order is $\boxed{\frac{7}{15}, \frac{2}{3}, \frac{4}{5}, \frac{9}{10}}$- 3(f):
Simplify to 1.
Find the LCM of the denominators (3, 5, 6, 1), which is 30.
Convert each fraction to an equivalent fraction with denominator 30.
$$ \frac{2}{3} = \frac{2 \times 10}{3 \times 10} = \frac{20}{30} $$ $$ \frac{1}{5} = \frac{1 \times 6}{5 \times 6} = \frac{6}{30} $$ $$ \frac{5}{6} = \frac{5 \times 5}{6 \times 5} = \frac{25}{30} $$ $$ \frac{2}{2} = 1 = \frac{30}{30} $$Arrange the fractions in ascending order.
$$ \frac{6}{30} < \frac{20}{30} < \frac{25}{30} < \frac{30}{30} $$Write the original fractions in ascending order.
$$ \frac{1}{5} < \frac{2}{3} < \frac{5}{6} < \frac{2}{2} $$ The ascending order is $\boxed{\frac{1}{5}, \frac{2}{3}, \frac{5}{6}, \frac{2}{2}}$4. Arrange in descending order.
- 4(a):
Find the LCM of the denominators (14, 7, 21), which is 42.
Convert each fraction to an equivalent fraction with denominator 42.
$$ \frac{9}{14} = \frac{9 \times 3}{14 \times 3} = \frac{27}{42} $$ $$ \frac{5}{7} = \frac{5 \times 6}{7 \times 6} = \frac{30}{42} $$ $$ \frac{11}{21} = \frac{11 \times 2}{21 \times 2} = \frac{22}{42} $$Arrange the fractions in descending order based on their numerators.
$$ \frac{30}{42} > \frac{27}{42} > \frac{22}{42} $$Write the original fractions in descending order.
$$ \frac{5}{7} > \frac{9}{14} > \frac{11}{21} $$ The descending order is $\boxed{\frac{5}{7}, \frac{9}{14}, \frac{11}{21}}$- 4(b):
Find the LCM of the denominators (8, 6, 12), which is 24.
Convert each fraction to an equivalent fraction with denominator 24.
$$ \frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24} $$ $$ \frac{1}{6} = \frac{1 \times 4}{6 \times 4} = \frac{4}{24} $$ $$ \frac{5}{12} = \frac{5 \times 2}{12 \times 2} = \frac{10}{24} $$Arrange the fractions in descending order.
$$ \frac{10}{24} > \frac{9}{24} > \frac{4}{24} $$Write the original fractions in descending order.
$$ \frac{5}{12} > \frac{3}{8} > \frac{1}{6} $$ The descending order is $\boxed{\frac{5}{12}, \frac{3}{8}, \frac{1}{6}}$- 4(c):
Find the LCM of the denominators (30, 5, 15), which is 30.
Convert each fraction to an equivalent fraction with denominator 30.
$$ \frac{19}{30} $$ $$ \frac{2}{5} = \frac{2 \times 6}{5 \times 6} = \frac{12}{30} $$ $$ \frac{7}{15} = \frac{7 \times 2}{15 \times 2} = \frac{14}{30} $$Arrange the fractions in descending order.
$$ \frac{19}{30} > \frac{14}{30} > \frac{12}{30} $$Write the original fractions in descending order.
$$ \frac{19}{30} > \frac{7}{15} > \frac{2}{5} $$ The descending order is $\boxed{\frac{19}{30}, \frac{7}{15}, \frac{2}{5}}$- 4(d):
Find the LCM of the denominators (3, 4, 5, 6), which is 60.
Convert each fraction to an equivalent fraction with denominator 60.
$$ \frac{2}{3} = \frac{2 \times 20}{3 \times 20} = \frac{40}{60} $$ $$ \frac{3}{4} = \frac{3 \times 15}{4 \times 15} = \frac{45}{60} $$ $$ \frac{4}{5} = \frac{4 \times 12}{5 \times 12} = \frac{48}{60} $$ $$ \frac{5}{6} = \frac{5 \times 10}{6 \times 10} = \frac{50}{60} $$Arrange the fractions in descending order.
$$ \frac{50}{60} > \frac{48}{60} > \frac{45}{60} > \frac{40}{60} $$Write the original fractions in descending order.
$$ \frac{5}{6} > \frac{4}{5} > \frac{3}{4} > \frac{2}{3} $$ The descending order is $\boxed{\frac{5}{6}, \frac{4}{5}, \frac{3}{4}, \frac{2}{3}}$- 4(e):
Find the LCM of the denominators (8, 10, 6, 12), which is 120.
Convert each fraction to an equivalent fraction with denominator 120.
$$ \frac{7}{8} = \frac{7 \times 15}{8 \times 15} = \frac{105}{120} $$ $$ \frac{3}{10} = \frac{3 \times 12}{10 \times 12} = \frac{36}{120} $$ $$ \frac{5}{6} = \frac{5 \times 20}{6 \times 20} = \frac{100}{120} $$ $$ \frac{11}{12} = \frac{11 \times 10}{12 \times 10} = \frac{110}{120} $$Arrange the fractions in descending order.
$$ \frac{110}{120} > \frac{105}{120} > \frac{100}{120} > \frac{36}{120} $$Write the original fractions in descending order.
$$ \frac{11}{12} > \frac{7}{8} > \frac{5}{6} > \frac{3}{10} $$ The descending order is $\boxed{\frac{11}{12}, \frac{7}{8}, \frac{5}{6}, \frac{3}{10}}$- 4(f):
Since the numerators are the same, the fraction with the smallest denominator is the largest.
Arrange in descending order.
$$ \frac{5}{6} > \frac{5}{7} > \frac{5}{9} > \frac{5}{12} $$ The descending order is $\boxed{\frac{5}{6}, \frac{5}{7}, \frac{5}{9}, \frac{5}{12}}$5. Shashank and Vikas have the same storybook. Shashank has read of the book and Vikas has read of the book. Who has read more pages?
Compare the fractions and .
Since the numerators are the same, the fraction with the smaller denominator is larger.
Conclude who read more.
Shashank has read more pages.
The answer is
6. Reena and Vineeta are classmates. Reena completed her homework in of an hour and Vineeta in of an hour. Who was faster?
To find who was faster, we need to find who took less time.
Compare and .
Find the LCM of the denominators (6, 4), which is 12.
Convert each fraction to an equivalent fraction with denominator 12.
Compare the times.
Conclude who was faster (took less time).
Vineeta took less time, so Vineeta was faster.
The answer is
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