Ships X, Y, and Z are sailing in relation to a harbour H. Ship X is 16 km from H on a bearing of 090°. Ship Y is 14 km from H on a bearing of 130°. Ship Z is 26.31 km from H on a bearing of 240°. Calc

Let H be the harbour.
Ship X is 16 km from H on a bearing of $090^\circ$. So, $HX = 16$ km.
Ship Y is 14 km from H on a bearing of $130^\circ$. So, $HY = 14$ km.
Ship Z is described with two pieces of information: "26.31 Km to the west of Y" and "on a bearing of $240^\circ$ from the harbour". These two pieces of information are contradictory if interpreted strictly. For typical bearing problems, when a distance and bearing from the harbour are given for a ship, that distance refers to the distance from the harbour. Therefore, we will assume that the distance of Z from the harbour