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Simplify 2/5 + 1/6

Mathematics

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C

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9. Simplify 25+1635\frac{\frac{2}{5} + \frac{1}{6}}{\frac{3}{5}}

  1. Simplify the numerator 25+16\frac{2}{5} + \frac{1}{6}.

    The least common multiple (LCM) of 5 and 6 is 30.

    25+16=2×65×6+1×56×5=1230+530=12+530=1730\frac{2}{5} + \frac{1}{6} = \frac{2 \times 6}{5 \times 6} + \frac{1 \times 5}{6 \times 5} = \frac{12}{30} + \frac{5}{30} = \frac{12+5}{30} = \frac{17}{30}
  2. Divide the simplified numerator by the denominator 35\frac{3}{5}.

    173035=1730÷35\frac{\frac{17}{30}}{\frac{3}{5}} = \frac{17}{30} \div \frac{3}{5}

    To divide by a fraction, multiply by its reciprocal.

    1730×53=17×530×3=8590\frac{17}{30} \times \frac{5}{3} = \frac{17 \times 5}{30 \times 3} = \frac{85}{90}
  3. Simplify the resulting fraction.

    Divide both the numerator and the denominator by their greatest common divisor, which is 5.

    85÷590÷5=1718\frac{85 \div 5}{90 \div 5} = \frac{17}{18}

    The correct option is not listed among A, B, C, D, E. Let me recheck my calculation.

    Recheck Step 2:

    1730×53=17×51306×3=17×16×3=1718\frac{17}{30} \times \frac{5}{3} = \frac{17 \times \cancel{5}^1}{\cancel{30}^6 \times 3} = \frac{17 \times 1}{6 \times 3} = \frac{17}{18}

    The calculation is correct. The answer is 1718\frac{17}{18}. None of the options match this result.

    10. Which of the fraction 536,13,512,29\frac{5}{36}, \frac{1}{3}, \frac{5}{12}, \frac{2}{9} and 718\frac{7}{18} is the largest?

  4. Find a common denominator for all fractions.

    The denominators are 36, 3, 12, 9, and 18. The least common multiple (LCM) of these numbers is 36.

  5. Convert each fraction to an equivalent fraction with a denominator of 36.

    536\frac{5}{36} 13=1×123×12=1236\frac{1}{3} = \frac{1 \times 12}{3 \times 12} = \frac{12}{36} 512=5×312×3=1536\frac{5}{12} = \frac{5 \times 3}{12 \times 3} = \frac{15}{36} 29=2×49×4=836\frac{2}{9} = \frac{2 \times 4}{9 \times 4} = \frac{8}{36} 718=7×218×2=1436\frac{7}{18} = \frac{7 \times 2}{18 \times 2} = \frac{14}{36}
  6. Compare the numerators to find the largest fraction.

    The numerators are 5, 12, 15, 8, 14. The largest numerator is 15.
    Therefore, the largest fraction is 1536\frac{15}{36}, which is equivalent to 512\frac{5}{12}.
    The correct option is C.

    11. Simplify 1131\frac{1}{3} of 38÷12\frac{3}{8} \div \frac{1}{2}

  7. Convert the mixed number to an improper fraction.

    113=(1×3)+13=431\frac{1}{3} = \frac{(1 \times 3) + 1}{3} = \frac{4}{3}

    The expression becomes 43\frac{4}{3} of 38÷12\frac{3}{8} \div \frac{1}{2}.

  8. Perform the division operation first (following order of operations, "of" is multiplication, which has the same precedence as division, but typically evaluated left-to-right or division before multiplication if "of" is interpreted as a grouping).

    Let's treat "of" as multiplication and follow standard order of operations (PEMDAS/BODMAS), so division before multiplication.

    38÷12=38×21=3×28×1=68=34\frac{3}{8} \div \frac{1}{2} = \frac{3}{8} \times \frac{2}{1} = \frac{3 \times 2}{8 \times 1} = \frac{6}{8} = \frac{3}{4}
  9. Perform the "of" operation (multiplication).

    43×34=4×33×4=1212=1\frac{4}{3} \times \frac{3}{4} = \frac{4 \times 3}{3 \times 4} = \frac{12}{12} = 1

    The correct option is D.

    12. Olu spent 12\frac{1}{2} of his pocket money on food, 14\frac{1}{4} of the remainder on transport. If he was left with N30, how much was Olu's pocket money?

  10. Let Olu's total pocket money be PP.

    Money spent on food = 12P\frac{1}{2}P.

  11. Calculate the remainder after spending on food.

    Remainder = P−12P=12PP - \frac{1}{2}P = \frac{1}{2}P.

  12. Calculate money spent on transport.

    Money spent on transport = 14\frac{1}{4} of the remainder = 14×12P=18P\frac{1}{4} \times \frac{1}{2}P = \frac{1}{8}P.

  13. Calculate the total money spent.

    Total spent = Money on food + Money on transport = 12P+18P\frac{1}{2}P + \frac{1}{8}P.
    To add these, find a common denominator (8):

    48P+18P=58P\frac{4}{8}P + \frac{1}{8}P = \frac{5}{8}P
  14. Calculate the money left and set it equal to N30.

    Money left = Total pocket money - Total spent

    P−58P=38PP - \frac{5}{8}P = \frac{3}{8}P

    We are given that he was left with N30.

    38P=30\frac{3}{8}P = 30
  15. Solve for PP.

    P=30×83P = 30 \times \frac{8}{3} P=30×83=2403=80P = \frac{30 \times 8}{3} = \frac{240}{3} = 80

    Olu's pocket money was N80.00.
    The correct option is B.

    13. Simplify 0.024×2.80.12×0.28\frac{0.024 \times 2.8}{0.12 \times 0.28}

  16. Rewrite the decimals as fractions to simplify.

    0.024=2410000.024 = \frac{24}{1000} 2.8=28102.8 = \frac{28}{10} 0.12=121000.12 = \frac{12}{100} 0.28=281000.28 = \frac{28}{100}
  17. Substitute these into the expression.

    241000×281012100×28100=24×281000012×2810000\frac{\frac{24}{1000} \times \frac{28}{10}}{\frac{12}{100} \times \frac{28}{100}} = \frac{\frac{24 \times 28}{10000}}{\frac{12 \times 28}{10000}}
  18. Simplify the expression.

    24×2810000÷12×2810000=24×2810000×1000012×28\frac{24 \times 28}{10000} \div \frac{12 \times 28}{10000} = \frac{24 \times 28}{10000} \times \frac{10000}{12 \times 28}

    Cancel out common terms: 28 and 10000.

    2412=2\frac{24}{12} = 2

    The correct option is E. (The options provided in the image are A. 0.0002, B. 0.002, C. 0.02, D. 0.2. There is no E option visible, but the answer is 2. Assuming there's an option E=2 or similar, I will provide the calculated answer.)
    The calculated answer is 2\boxed{2}.

    14. From 19.35 subtract 8.972.

  19. Align the decimal points and add trailing zeros to ensure equal decimal places.

    019.350−008.972\begin{array}{c} \phantom{0}19.350 \\ -\phantom{00}8.972 \\ \hline \end{array}
  20. Perform the subtraction.

    019.350−008.97210.378\begin{array}{c} \phantom{0}19.350 \\ -\phantom{00}8.972 \\ \hline 10.378 \\ \end{array}

    The result is 10.378.
    The correct option is D.

    15. Reduce 0.075 to a fraction in its lowest term.

  21. Convert the decimal to a fraction.

    0.075 means 75 thousandths.

    0.075=7510000.075 = \frac{75}{1000}
  22. Simplify the fraction to its lowest terms by dividing the numerator and denominator by their greatest common divisor.

    Both 75 and 1000 are divisible by 25.

    75÷251000÷25=340\frac{75 \div 25}{1000 \div 25} = \frac{3}{40}

    The fraction in its lowest term is 340\frac{3}{40}.
    The correct option is A.

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