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Simplify sqrt(5)+3sqrt(5)-2. Give the answer in the form a + bsqrt(c) where a, b and c are integers.

Mathematics

ScanSolve AI Answer

Answer

11+5511 + 5\sqrt{5}

1:5
250

Step-by-step solution

8 steps
  1. Kurahisisha usemi

    Ili kurahisisha usemi 5+35−2\frac{\sqrt{5}+3}{\sqrt{5}-2}, tunazidisha nambari na denominata kwa kiambishi cha denominata, ambacho ni 5+2\sqrt{5}+2.

    5+35−2×5+25+2\frac{\sqrt{5}+3}{\sqrt{5}-2} \times \frac{\sqrt{5}+2}{\sqrt{5}+2}
  2. Kupanua nambari na denominata

    Panua nambari:

    (5+3)(5+2)=5⋅5+5⋅2+3⋅5+3⋅2(\sqrt{5}+3)(\sqrt{5}+2) = \sqrt{5}\cdot\sqrt{5} + \sqrt{5}\cdot2 + 3\cdot\sqrt{5} + 3\cdot2 =5+25+35+6= 5 + 2\sqrt{5} + 3\sqrt{5} + 6 =11+55= 11 + 5\sqrt{5}

    Panua denominata (kumbuka (a−b)(a+b)=a2−b2(a-b)(a+b) = a^2-b^2):

    (5−2)(5+2)=(5)2−(2)2(\sqrt{5}-2)(\sqrt{5}+2) = (\sqrt{5})^2 - (2)^2 =5−4= 5 - 4 =1= 1
  3. Kuweka pamoja na kurahisisha

    Sasa weka nambari na denominata pamoja:

    11+551=11+55\frac{11 + 5\sqrt{5}}{1} = 11 + 5\sqrt{5}

    Hii iko katika mfumo a+bca + b\sqrt{c} ambapo a=11a=11, b=5b=5, na c=5c=5.

    11+55\boxed{11 + 5\sqrt{5}}

    2. Uwiano wa unga X:Y

  4. Kuunda mlinganyo

    Acha xx iwe kiasi cha unga X na yy iwe kiasi cha unga Y.
    Gharama ya unga X ni Ksh 60 kwa kg, na unga Y ni Ksh 72 kwa kg.
    Gharama ya mchanganyiko ni Ksh 70 kwa kg.
    Gharama ya jumla ya mchanganyiko ni 60x+72y60x + 72y.
    Kiasi cha jumla cha mchanganyiko ni x+yx + y.
    Gharama kwa kg ya mchanganyiko ni 60x+72yx+y=70\frac{60x + 72y}{x + y} = 70.

  5. Kutatua mlinganyo kwa uwiano x:yx:y

    60x+72yx+y=70\frac{60x + 72y}{x + y} = 70

    Zidisha pande zote mbili kwa (x+y)(x+y):

    60x+72y=70(x+y)60x + 72y = 70(x + y) 60x+72y=70x+70y60x + 72y = 70x + 70y

    Panga upya vigezo:

    72y−70y=70x−60x72y - 70y = 70x - 60x 2y=10x2y = 10x

    Ili kupata uwiano x:yx:y, gawanya pande zote mbili kwa yy na kwa 10:

    2y10y=10x10y\frac{2y}{10y} = \frac{10x}{10y} 210=xy\frac{2}{10} = \frac{x}{y} 15=xy\frac{1}{5} = \frac{x}{y}

    Hivyo, uwiano x:yx:y ni 1:51:5.

    1:5\boxed{1:5}

    3. Kuamua P wakati L = 0.2

  6. Kuunda mlinganyo wa utofauti

    Kiasi P kinatofautiana kinyume na mraba wa kiasi kingine L. Hii inaweza kuandikwa kama:

    P=kL2P = \frac{k}{L^2}

    ambapo kk ni kigezo cha utofauti.

  7. Kupata thamani ya kigezo kk

    Tunapewa P=0.625P = 0.625 wakati L=4L = 4. Badilisha hizi kwenye mlinganyo:

    0.625=k420.625 = \frac{k}{4^2} 0.625=k160.625 = \frac{k}{16}

    Ili kupata kk, zidisha pande zote mbili kwa 16:

    k=0.625×16k = 0.625 \times 16 k=10k = 10
  8. Kuamua P wakati L=0.2L = 0.2

    Sasa tunajua k=10k = 10. Tunataka kupata P wakati L=0.2L = 0.2. Badilisha hizi kwenye mlinganyo wa utofauti:

    P=10(0.2)2P = \frac{10}{(0.2)^2} P=100.04P = \frac{10}{0.04} P=104100P = \frac{10}{\frac{4}{100}} P=10×1004P = 10 \times \frac{100}{4} P=10004P = \frac{1000}{4} P=250P = 250 250\boxed{250}
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