Simplify the expression: (16)/(12) x (6)/(9) x (12)/(8)

• The 12 in the denominator of the first fraction and the 12 in the numerator of the third fraction cancel each other out.

$$\frac{16}{\cancel{12}_1} \times \frac{6}{9} \times \frac{\cancel{12}^1}{8}$$

• The 16 in the numerator of the first fraction and the 8 in the denominator of the third fraction can be simplified. Divide both by 8: $16 \div 8 = 2$ and $8 \div 8 = 1$.

$$\frac{\cancel{16}^2}{1} \times \frac{6}{9} \times \frac{1}{\cancel{8}_1}$$

• The 6 in the numerator of the second fraction and the 9 in its denominator can be simplified. Divide both by 3: $6 \div 3 = 2$ and $9 \div 3 = 3$.

$$\frac{2}{1} \times \frac{\cancel{6}^2}{\cancel{9}_3} \times \frac{1}{1}$$

$$\frac{2 \times 2 \times 1}{1 \times 3 \times 1} = \frac{4}{3}$$

The final answer is $\frac{4}{3}$.