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Simplify the following algebraic expressions: (a3+1)/(a2-a+1) + (a3-1)/(a2+a+1) and (m2+mn+n2)/(m+n) + (m2-mn+n2)/(m-n)

Mathematics

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:

a3+1a2−a+1+a3−1a2+a+1\frac{a^3+1}{a^2-a+1} + \frac{a^3-1}{a^2+a+1}
  1. Factor the numerators using the sum and difference of cubes formulas, x3+y3=(x+y)(x2−xy+y2)x^3+y^3 = (x+y)(x^2-xy+y^2) and x3−y3=(x−y)(x2+xy+y2)x^3-y^3 = (x-y)(x^2+xy+y^2).

    a3+1=(a+1)(a2−a+1)a^3+1 = (a+1)(a^2-a+1) a3−1=(a−1)(a2+a+1)a^3-1 = (a-1)(a^2+a+1)
  2. Substitute the factored forms into the expression.

    (a+1)(a2−a+1)a2−a+1+(a−1)(a2+a+1)a2+a+1\frac{(a+1)(a^2-a+1)}{a^2-a+1} + \frac{(a-1)(a^2+a+1)}{a^2+a+1}
  3. Cancel out common terms in the numerators and denominators.

    (a+1)+(a−1)(a+1) + (a-1)
  4. Simplify the expression.

    a+1+a−1=2aa+1+a-1 = 2a

    The final answer is 2a\boxed{2a}.

    :

    m2+mn+n2m+n+m2−mn+n2m−n\frac{m^2+mn+n^2}{m+n} + \frac{m^2-mn+n^2}{m-n}
  5. Find a common

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