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Simplify the following expressions: a) 130 b) 131 c) 132 d) (6+10)0 e) (3 imes 4)1 f) (12 imes 24)0

Mathematics

ScanSolve AI Answer

Answers

6 parts
a
1
b
13
c
169
d
1
e
12
f
1

Step-by-step solution

9 steps

Part a· 1 step

  1. Apply the rule that any non-zero number raised to the power of 0 is 1.

    130=113^0 = 1

    The value is 1\boxed{1}.

Part b13

  1. Apply the rule that any number raised to the power of 1 is itself.

    131=1313^1 = 13

    The value is 13\boxed{13}.

Part c169

  1. Calculate 13 raised to the power of 2.

    132=13×13=16913^2 = 13 \times 13 = 169

    The value is 169\boxed{169}.

Part d1

  1. First, calculate the sum inside the parentheses.

    6+10=166+10 = 16
  2. Apply the rule that any non-zero number raised to the power of 0 is 1.

    (6+10)0=160=1(6+10)^0 = 16^0 = 1

    The value is 1\boxed{1}.

Part e12

  1. First, calculate the product inside the parentheses.

    3×4=123 \times 4 = 12
  2. Apply the rule that any number raised to the power of 1 is itself.

    (3×4)1=121=12(3 \times 4)^1 = 12^1 = 12

    The value is 12\boxed{12}.

Part f1

  1. First, calculate the product inside the parentheses.

    12×24=28812 \times 24 = 288
  2. Apply the rule that any non-zero number raised to the power of 0 is 1.

    (12×24)0=2880=1(12 \times 24)^0 = 288^0 = 1

    The value is 1\boxed{1}.

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