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Simplify the following rational expressions. Problems include addition, subtraction, and factoring.

Mathematics

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Answer

0\text{0}

Step-by-step solution

5 steps

यहाँ दिइएको व्यञ्जकलाई सरल बनाउनुपर्छ:

1(x−2)(x−3)+1(x−2)(x−1)−2(x−3)(x−1)\frac{1}{(x-2)(x-3)} + \frac{1}{(x-2)(x-1)} - \frac{2}{(x-3)(x-1)}
  1. सबै भिन्नहरूको साझा हर (common denominator) पत्ता लगाउनुहोस्।

    दिएका हरहरू (x−2)(x−3)(x-2)(x-3), (x−2)(x−1)(x-2)(x-1), र (x−3)(x−1)(x-3)(x-1) हुन्। यिनीहरूको लघुत्तम समापवर्त्य (LCM) (x−1)(x−2)(x−3)(x-1)(x-2)(x-3) हुन्छ।

  2. प्रत्येक भिन्नलाई साझा हरमा रूपान्तरण गर्नुहोस्।

    पहिलो भिन्न:

    1(x−2)(x−3)=1⋅(x−1)(x−2)(x−3)(x−1)=x−1(x−1)(x−2)(x−3)\frac{1}{(x-2)(x-3)} = \frac{1 \cdot (x-1)}{(x-2)(x-3)(x-1)} = \frac{x-1}{(x-1)(x-2)(x-3)}

    दोस्रो भिन्न:

    1(x−2)(x−1)=1⋅(x−3)(x−2)(x−1)(x−3)=x−3(x−1)(x−2)(x−3)\frac{1}{(x-2)(x-1)} = \frac{1 \cdot (x-3)}{(x-2)(x-1)(x-3)} = \frac{x-3}{(x-1)(x-2)(x-3)}

    तेस्रो भिन्न:

    2(x−3)(x−1)=2⋅(x−2)(x−3)(x−1)(x−2)=2(x−2)(x−1)(x−2)(x−3)\frac{2}{(x-3)(x-1)} = \frac{2 \cdot (x-2)}{(x-3)(x-1)(x-2)} = \frac{2(x-2)}{(x-1)(x-2)(x-3)}
  3. सबै भिन्नहरूलाई साझा हरमा जोड्नुहोस् र घटाउनुहोस्।

    (x−1)+(x−3)−2(x−2)(x−1)(x−2)(x−3)\frac{(x-1) + (x-3) - 2(x-2)}{(x-1)(x-2)(x-3)}
  4. अंश (numerator) लाई सरल बनाउनुहोस्।

    अंश =(x−1)+(x−3)−2(x−2)= (x-1) + (x-3) - 2(x-2)
    अंश =x−1+x−3−(2x−4)= x - 1 + x - 3 - (2x - 4)
    अंश =x−1+x−3−2x+4= x - 1 + x - 3 - 2x + 4
    अंश =(x+x−2x)+(−1−3+4)= (x + x - 2x) + (-1 - 3 + 4)
    अंश =0x+0= 0x + 0
    अंश =0= 0

  5. अन्तिम परिणाम लेख्नुहोस्।

    0(x−1)(x−2)(x−3)=0\frac{0}{(x-1)(x-2)(x-3)} = 0

    अतः, सरल बनाउँदा प्राप्त हुने मान 0 हो।

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