Sketch the following graphs: y = -3x2, y = -2x2 - 8, and y = x2 - 9 using the table method for x ","-2, -1, 0, 1, 2. State the domain and range for each.

Here are the solutions to the assessment activity: Assessment activity 2.4 1. Sketch the following graphs. Use the table method for the given x-values x \-2; -1; 0; 1; 2\. Write down the domain and range of each graph. (Note: I cannot provide a visual sketch. The tables of values, shape descriptions, domain, and range are provided below.) 1(a) y = -3x^2 Step 1: Create a table of values. |c|c| x & y = -3x^2 \\ -2 & -12 \\ -1 & -3 \\ 0 & 0 \\ 1 & -3 \\ 2 & -12 \\ The graph is a parabola opening downwards with its vertex at (0,0). Step 2: Determine the domain and range. Domain: x R Range: y 0 1(b) y = -2x^2 - 8 Step 1: Create a table of values. |c|c| x & y = -2x^2 - 8 \\ -2 & -16 \\ -1 & -10 \\ 0 & -8 \\ 1 & -10 \\ 2 & -16 \\ The graph is a parabola opening downwards with its vertex at (0,-8). Step 2: Determine the domain and range. Domain: x R Range: y -8 1(c) y = x^2 - 9 Step 1: Create a table of values. |c|c| x & y = x^2 - 9 \\ -2 & -5 \\ -1 & -8 \\ 0 & -9 \\ 1 & -8 \\ 2 & -5 \\ The graph is a parabola opening upwards with its vertex at (0,-9). Step 2: Determine the domain and range. Domain: x R Range: y -9 2. Given: y = 4x^2 - 8. Determine the following: 2(a) Shape of the graph Step 1: The coefficient of x^2 is 4, which is positive. The graph is a parabola opening upwards. 2(b) x-intercept(s) Step 1: Set y=0. 0 = 4x^2 - 8 Step 2: Solve for x. 4x^2 = 8 x^2 = (8)/(4) x^2 = 2 x = ± sqrt(2) The x-intercepts