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Solve: 2 3 4 2 & 5 & 3 4 & 6 & 7 -1 & 1 & 0

Mathematics

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Answer

(31541)\begin{pmatrix} 31 \\ 54 \\ 1 \end{pmatrix}

Step-by-step solution

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Kutokana na picha, tuna matriki mbili:
Matriki ya kwanza (kushoto): A=(234)A = \begin{pmatrix} 2 \\ 3 \\ 4 \end{pmatrix}
Matriki ya pili (kulia): B=(253467−110)B = \begin{pmatrix} 2 & 5 & 3 \\ 4 & 6 & 7 \\ -1 & 1 & 0 \end{pmatrix}

Ukubwa wa matriki AA ni 3×13 \times 1 (safu mlalo 3, safu wima 1).
Ukubwa wa matriki BB ni 3×33 \times 3 (safu mlalo 3, safu wima 3).

Ili kuzidisha matriki A×BA \times B, idadi ya safu wima za matriki AA lazima iwe sawa na idadi ya safu mlalo za matriki BB. Katika kesi hii, AA ina safu wima 1 na BB ina safu mlalo 3. Kwa kuwa 1≠31 \neq 3, kuzidisha A×BA \times B hakujafafanuliwa.

Hata hivyo, mara nyingi maswali kama haya yanamaanisha kuzidisha kwa mpangilio ambao unawezekana. Kuzidisha B×AB \times A kunawezekana kwa sababu idadi ya safu wima za BB (3) ni sawa na idadi ya safu mlalo za AA (3). Matokeo yatakuwa matriki ya 3×13 \times 1.

Tutafanya hesabu kwa kuzidisha B×AB \times A.

  1. Andika matriki kwa mpangilio wa kuzidisha B×AB \times A.

    (253467−110)(234)\begin{pmatrix} 2 & 5 & 3 \\ 4 & 6 & 7 \\ -1 & 1 & 0 \end{pmatrix} \begin{pmatrix} 2 \\ 3 \\ 4 \end{pmatrix}
  2. Kokotoa elementi ya kwanza ya matriki ya matokeo.

    Zidisha safu mlalo ya kwanza ya matriki BB na safu wima ya matriki AA:

    (2×2)+(5×3)+(3×4)=4+15+12=31(2 \times 2) + (5 \times 3) + (3 \times 4) = 4 + 15 + 12 = 31
  3. Kokotoa elementi ya pili ya matriki ya matokeo.

    Zidisha safu mlalo ya pili ya matriki BB na safu wima ya matriki AA:

    (4×2)+(6×3)+(7×4)=8+18+28=54(4 \times 2) + (6 \times 3) + (7 \times 4) = 8 + 18 + 28 = 54
  4. Kokotoa elementi ya tatu ya matriki ya matokeo.

    Zidisha safu mlalo ya tatu ya matriki BB na safu wima ya matriki AA:

    (−1×2)+(1×3)+(0×4)=−2+3+0=1(-1 \times 2) + (1 \times 3) + (0 \times 4) = -2 + 3 + 0 = 1
  5. Andika matriki ya matokeo.

    Matokeo ya kuzidisha B×AB \times A ni:

    (31541)\begin{pmatrix} 31 \\ 54 \\ 1 \end{pmatrix}
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