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Solve: 2(x + 4)−x+5=4

Mathematics

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Swali la 23:

a) Tatua: 2(x+4)−x+5=42(x+4) - x + 5 = 4

Step 1: Panua mabano.

2x+8−x+5=42x + 8 - x + 5 = 4

Step 2: Unganisha vigezo vya xx na namba zisizobadilika.

(2x−x)+(8+5)=4(2x - x) + (8 + 5) = 4 x+13=4x + 13 = 4

Step 3: Tenga xx kwa kutoa 13 kutoka pande zote mbili.

x=4−13x = 4 - 13 x=−9x = \boxed{-9}

b) Tatua na uonyeshe seti ya suluhisho ya usawa ufuatao kwenye mstari wa namba: 3x+4≥2x+73x + 4 \ge 2x + 7

Step 1: Peleka vigezo vya xx upande mmoja na namba zisizobadilika upande mwingine.

3x−2x≥7−43x - 2x \ge 7 - 4

Step 2: Rahisisha usawa.

x≥3x \ge 3

Step 3: Onyesha suluhisho kwenye mstari wa namba. Mstari wa namba utakuwa na duara lililojazwa kwenye 3 na mshale unaoelekea kulia.

Suluhisho ni x≥3\text{Suluhisho ni } \boxed{x \ge 3}

(Mchoro wa mstari wa namba unaonyesha duara lililojazwa kwenye namba 3 na mshale unaoelekea upande wa kulia, kuwakilisha namba zote kubwa au sawa na 3.)

Swali la 24:

a) Baada ya muda gani magari hayo mawili yatakutana?

Gari linaondoka Mji A saa 7:00 asubuhi kwa kasi ya 40 km/h kuelekea Mji B, ambao uko umbali wa 40 km.
Basi linaondoka Mji B saa 8:00 asubuhi kwa kasi ya 60 km/h kuelekea Mji A.

Step 1: Kokotoa umbali uliosafiriwa na gari kufikia saa 8:00 asubuhi.
Gari lilisafiri kwa saa 1 (kutoka 7:00 asubuhi hadi 8:00 asubuhi).

Umbali wa gari=Kasi×Muda=40 km/h×1 h=40 km\text{Umbali wa gari} = \text{Kasi} \times \text{Muda} = 40 \text{ km/h} \times 1 \text{ h} = 40 \text{ km}

Step 2: Tambua mahali pa kukutania.
Kwa kuwa Mji B uko umbali wa 40 km kutoka Mji A, gari linafika Mji B saa 8:00 asubuhi.
Basi linaondoka Mji B saa 8:00 asubuhi.
Hivyo, magari hayo mawili yanakutana Mji B saa 8:00 asubuhi.

Step 3: Kokotoa muda tangu gari lianze safari.
Gari lilianza saa 7:00 asubuhi na walikutana saa 8:00 asubuhi.

Muda=8:00 asubuhi−7:00 asubuhi=1 saa\text{Muda} = 8:00 \text{ asubuhi} - 7:00 \text{ asubuhi} = \boxed{1 \text{ saa}}

b) Ni umbali gani kutoka mahali pa kukutania hadi Mji A?

Step 1: Mahali pa kukutania ni Mji B.

Step 2: Umbali kutoka Mji B hadi Mji A umetolewa kwenye swali.

Umbali=40 km\text{Umbali} = \boxed{40 \text{ km}}

Swali la 25:

a) Kuna watu wazima wangapi?

Tutafanya dhana zifuatazo kutokana na uandishi usio wazi wa swali:

  • "men" na "women" wanarejelea watu wazima.
  • "girls" wanarejelea watoto wa kike.
  • "14\frac{1}{4} of the are men" inamaanisha 14\frac{1}{4} ya watu wazima ni wanaume.
  • "120 are women" inamaanisha idadi ya wanawake wazima ni 120.
  • "If the number of girls is equal to the number of women" inamaanisha idadi ya watoto wa kike ni sawa na idadi ya wanawake wazima.

Step 1: Weka uwiano wa watu wazima na watoto.
Jumla ya idadi ya watu = PP.
Watu wazima = 25P\frac{2}{5} P.
Watoto = P−25P=35PP - \frac{2}{5} P = \frac{3}{5} P.

Step 2: Tafuta uwiano wa wanawake wazima.
Wanaume wazima = 14×(Watu wazima)=14×25P=110P\frac{1}{4} \times (\text{Watu wazima}) = \frac{1}{4} \times \frac{2}{5} P = \frac{1}{10} P.
Wanawake wazima = Watu wazima - Wanaume wazima = 25P−110P=410P−110P=310P\frac{2}{5} P - \frac{1}{10} P = \frac{4}{10} P - \frac{1}{10} P = \frac{3}{10} P.

Step 3: Tumia idadi ya wanawake wazima kupata jumla ya idadi ya watu (PP).
Tunajua wanawake wazima ni 120.

310P=120\frac{3}{10} P = 120 P=120×103P = 120 \times \frac{10}{3} P=40×10P = 40 \times 10 P=400P = 400

Step 4: Kokotoa idadi ya watu wazima.
Watu wazima = $\frac{2}{5} P = \frac{2}{5} \times 400 = 2 \times 80 = \boxed{160}$$

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