Identify the literary devices used in the poem and explain their effect.

$$\Delta H^\circ_\text{rxn} = \sum n \Delta H^\circ_f (\text{products}) - \sum n \Delta H^\circ_f (\text{reactants})$$

where $n$ is the stoichiometric coefficient.

$\Delta H^\circ_f (\ce{CO2(g)}) = -393.5$

$\Delta H^\circ_f (\ce{H2O(l)}) = -285.8$

$\Delta H^\circ_f (\ce{CH4(g)}) = -74.8$

$\Delta H^\circ_f (\ce{O2(g)}) = 0$

Products: $\ce{1 \cdot CO2(g) + 2 \cdot H2O(l)}$

$$\sum n \Delta H^\circ_f (\text{products}) = [1 \times (-393.5)] + [2 \times (-285.8)] \, \mathrm{kJ \, mol^{-1}}$$ $$= -393.5 + 2 \times (-285.8) \, \mathrm{kJ \, mol^{-1}}$$ $$= -393.5 - 571.6 \, \mathrm{kJ \, mol^{-1}}$$ $$= -965.1 \, \mathrm{kJ \, mol^{-1}}$$

Reactants: $\ce{1 \cdot CH4(g) + 2 \cdot O2(g)}$

$$\sum n \Delta H^\circ_f (\text{reactants}) = [1 \times (-74.8)] + [2 \times 0] \, \mathrm{kJ \, mol^{-1}}$$ $$= -74.8 + 0 \, \mathrm{kJ \, mol^{-1}}$$ $$= -74.8 \, \mathrm{kJ \, mol^{-1}}$$

$$\Delta H^\circ_\text{rxn} = [-965.1] - [-74.8] \, \mathrm{kJ \, mol^{-1}}$$ $$= -965.1 + 74.8 \, \mathrm{kJ \, mol^{-1}}$$ $$= -890.3 \, \mathrm{kJ \, mol^{-1}}$$

-890 kJ mol^{-1}