Starting from question 4-5

QUESTION ONE

3. Make y the subject: $p = \frac{2y-c}{m}$.

Step 2: Add $c$ to both sides.

$$pm + c = 2y$$

Step 3: Divide both sides by 2.

$$y = \frac{pm+c}{2}$$

The subject is $\boxed{y = \frac{pm+c}{2}}$.

4. The ratio of female to male student at NACE is 5:4. If the number of male students is 1000. Find the total number of students at NACE. Let $F$ be the number of female students and $M$ be the number of male students. Given ratio $F:M = 5:4$. Given $M = 1000$.

Step 1: Set up the ratio equation.

$$\frac{F}{M} = \frac{5}{4}$$

Step 2: Substitute the number of male students.

$$\frac{F}{1000} = \frac{5}{4}$$

Step 3: Solve for $F$.

$$F = \frac{5}{4} \times 1000$$ $$F = 5 \times 250$$ $$F = 1250$$

Step 4: Calculate the total number of students.
Total students = $F + M = 1250 + 1000 = 2250$.
The total number of students at NACE is $\boxed{2250}$.

5. The diagram below shows the position of town P and town Q. The diagram shows town Q with a North line (N) and a line segment QP. The angle between the North line at Q and the line segment QP is $70^\circ$.