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Find the table of value for 3x2 - 5x - 7

Mathematics

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To find the table of values for the expression 3x2−5x−73x^2 - 5x - 7, we need to choose a range of xx values and calculate the corresponding yy values. Since no specific range is given, we will use integer values for xx from −3-3 to 3.

  1. Define the function.

    Let y=3x2−5x−7y = 3x^2 - 5x - 7.

  2. Calculate yy for each chosen xx value.

    • For x=−3x = -3:
    y=3(−3)2−5(−3)−7=3(9)+15−7=27+15−7=42−7=35y = 3(-3)^2 - 5(-3) - 7 = 3(9) + 15 - 7 = 27 + 15 - 7 = 42 - 7 = 35
    • For x=−2x = -2:
    y=3(−2)2−5(−2)−7=3(4)+10−7=12+10−7=22−7=15y = 3(-2)^2 - 5(-2) - 7 = 3(4) + 10 - 7 = 12 + 10 - 7 = 22 - 7 = 15
    • For x=−1x = -1:
    y=3(−1)2−5(−1)−7=3(1)+5−7=3+5−7=8−7=1y = 3(-1)^2 - 5(-1) - 7 = 3(1) + 5 - 7 = 3 + 5 - 7 = 8 - 7 = 1
    • For x=0x = 0:
    y=3(0)2−5(0)−7=0−0−7=−7y = 3(0)^2 - 5(0) - 7 = 0 - 0 - 7 = -7
    • For x=1x = 1:
    y=3(1)2−5(1)−7=3(1)−5−7=3−5−7=−2−7=−9y = 3(1)^2 - 5(1) - 7 = 3(1) - 5 - 7 = 3 - 5 - 7 = -2 - 7 = -9
    • For x=2x = 2:
    y=3(2)2−5(2)−7=3(4)−10−7=12−10−7=2−7=−5y = 3(2)^2 - 5(2) - 7 = 3(4) - 10 - 7 = 12 - 10 - 7 = 2 - 7 = -5
    • For x=3x = 3:
    y=3(3)2−5(3)−7=3(9)−15−7=27−15−7=12−7=5y = 3(3)^2 - 5(3) - 7 = 3(9) - 15 - 7 = 27 - 15 - 7 = 12 - 7 = 5
  3. Present the values in a table.

    The table of values for y=3x2−5x−7y = 3x^2 - 5x - 7 for xx from −3-3 to 3 is:

    xy=3x2−5x−7−335−215−110−71−92−535\boxed{ \begin{array}{|c|c|} \hline x & y = 3x^2 - 5x - 7 \\ \hline -3 & 35 \\ -2 & 15 \\ -1 & 1 \\ 0 & -7 \\ 1 & -9 \\ 2 & -5 \\ 3 & 5 \\ \hline \end{array} }
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