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Tafuta thamani ya d, ikiwa AB ni mstari mnyofu

Mathematics

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Answer

64∘\text{64}^\circ

Step-by-step solution

4 steps
  1. Tambua aina ya poligoni na pembe zilizotolewa.

    Poligoni hii ina pande 5, kwa hivyo ni pentagoni.
    Mstari AB ni mstari mnyoofu.
    Pembe ya nje upande wa kushoto chini ni 70∘70^\circ.
    Pembe za ndani zilizobaki ni 2d2d, dd, na 2d2d.
    Kutokana na alama sawa za pembe za nje chini, tunadhania pembe ya nje upande wa kulia chini pia ni 70∘70^\circ.

  2. Kokotoa pembe za ndani za pentagoni.

    • Pembe ya ndani (chini kushoto): 180∘−70∘=110∘180^\circ - 70^\circ = 110^\circ.
    • Pembe ya ndani (juu kushoto): 2d2d.
    • Pembe ya ndani (juu katikati): dd.
    • Pembe ya ndani (juu kulia): 2d2d.
    • Pembe ya ndani (chini kulia): 180∘−70∘=110∘180^\circ - 70^\circ = 110^\circ.
  3. Tumia kanuni ya jumla ya pembe za ndani za poligoni.

    Kwa poligoni yenye pande nn, jumla ya pembe za ndani ni (n−2)×180∘(n-2) \times 180^\circ.
    Kwa pentagoni (n=5n=5):
    Jumla ya pembe za ndani =(5−2)×180∘=3×180∘=540∘= (5-2) \times 180^\circ = 3 \times 180^\circ = 540^\circ.

  4. Tengeneza mlinganyo kwa kutumia jumla ya pembe za ndani na utatue kwa dd.

    110∘+2d+d+2d+110∘=540∘110^\circ + 2d + d + 2d + 110^\circ = 540^\circ 220∘+5d=540∘220^\circ + 5d = 540^\circ 5d=540∘−220∘5d = 540^\circ - 220^\circ 5d=320∘5d = 320^\circ d=320∘5d = \frac{320^\circ}{5} d=64∘d = 64^\circ

    Thamani ya dd ni 64∘\boxed{\text{64}^\circ}.

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