We read your photo as:

Teacher Emily wrote the following operations on the board. Simplify the operations a)g b)

Mathematics

ScanSolve AI Answer

Answer

34\frac{3}{4}

12x11y512x^{11}y^5

6.54 m26.54 \text{ m}^2

Step-by-step solution

10 steps

Nimeona picha yako. Wacha tuendelee na maswali haya.

:
Ili kupata gradient (mteremko) wa mstari unaounganisha pointi mbili, tunatumia formula ya gradient.

  1. Andika formula ya gradient na pointi ulizopewa.

    Pointi ni A(x1,y1)=(0,0)A(x_1, y_1) = (0,0) na B(x2,y2)=(4,3)B(x_2, y_2) = (4,3).
    Formula ya gradient ni:

    m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}
  2. Badilisha thamani za pointi kwenye formula.

    m=3−04−0m = \frac{3 - 0}{4 - 0}
  3. Rahisisha ili kupata gradient.

    m=34m = \frac{3}{4}

    Gradient ya mstari unaounganisha pointi A na B ni 34\boxed{\frac{3}{4}}.

    :
    Ili kurahisisha usemi huu, tutatumia sheria za vipeo (exponents) na kurahisisha namba.

  4. Zidisha namba na vigezo (variables) kwenye nambari (numerator).

    9x7y3×4x6y43x2y2=(9×4)×(x7×x6)×(y3×y4)3x2y2\frac{9x^7y^3 \times 4x^6y^4}{3x^2y^2} = \frac{(9 \times 4) \times (x^7 \times x^6) \times (y^3 \times y^4)}{3x^2y^2}

    Tumia sheria am×an=am+na^m \times a^n = a^{m+n}:

    =36x7+6y3+43x2y2= \frac{36x^{7+6}y^{3+4}}{3x^2y^2} =36x13y73x2y2= \frac{36x^{13}y^7}{3x^2y^2}
  5. Gawanya namba na vigezo kwenye denominator (kigawanyo).

    Tumia sheria aman=am−n\frac{a^m}{a^n} = a^{m-n}:

    =(363)×(x13x2)×(y7y2)= \left(\frac{36}{3}\right) \times \left(\frac{x^{13}}{x^2}\right) \times \left(\frac{y^7}{y^2}\right) =12x13−2y7−2= 12x^{13-2}y^{7-2}
  6. Rahisisha vipeo.

    =12x11y5= 12x^{11}y^5

    Usemi uliorahisishwa ni 12x11y5\boxed{12x^{11}y^5}.

    :
    Ili kukokotoa eneo lililoangaziwa na spotlight, tunahitaji kutumia formula ya eneo la sekta ya duara.

  7. Tambua radius na angle.

    Kipenyo (diameter) D=10D = 10 m, hivyo radius r=D2=102=5r = \frac{D}{2} = \frac{10}{2} = 5 m.
    Angle ya sekta θ=30∘\theta = 30^\circ.

  8. Andika formula ya eneo la sekta.

    Eneo la sekta =θ360∘×πr2= \frac{\theta}{360^\circ} \times \pi r^2

  9. Badilisha thamani kwenye formula na kokotoa.

    Eneo=30∘360∘×π(5 m)2\text{Eneo} = \frac{30^\circ}{360^\circ} \times \pi (5 \text{ m})^2 Eneo=112×π(25 m2)\text{Eneo} = \frac{1}{12} \times \pi (25 \text{ m}^2) Eneo=25π12 m2\text{Eneo} = \frac{25\pi}{12} \text{ m}^2
  10. Kokotoa thamani ya namba (kwa kutumia π≈3.14159\pi \approx 3.14159).

    Eneo≈25×3.1415912 m2\text{Eneo} \approx \frac{25 \times 3.14159}{12} \text{ m}^2 Eneo≈78.5397512 m2\text{Eneo} \approx \frac{78.53975}{12} \text{ m}^2 Eneo≈6.544979 m2\text{Eneo} \approx 6.544979 \text{ m}^2

    Eneo lililoangaziwa na spotlight ni takriban 6.54 m2\boxed{6.54 \text{ m}^2} (kwa desimali mbili).

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp