The angle in a triangle are in the form x,2x,3x Find the difference between the smallest and the largest angle

The sum of the angles in any triangle is $180^\circ$. The given angles are $x$, $2x$, and $3x$.

Combine the terms on the left side of the equation.

Divide both sides by 6.

Substitute the value of $x$ back into the expressions for the angles.
Smallest angle: $x = 30^\circ$
Middle angle: $2x = 2(30^\circ) = 60^\circ$
Largest angle: $3x = 3(30^\circ) = 90^\circ$

Difference = Largest angle - Smallest angle
Difference = $90^\circ - 30^\circ$
Difference = $60^\circ$

The final answer is \boxed{\text{60^\circ}}.