We read your photo as:

What are the derivative rules for vector functions: constant multiple, sum, dot product, and cross product?

Mathematics

ScanSolve AI Answer

Here's the concept behind each formula:

  • a) ddu(cA)=cdAdu\frac{d}{du}(cA) = c\frac{dA}{du} This is the constant multiple rule for vector differentiation. It states that the derivative of a constant scalar cc multiplied by a vector function A(u)A(u) is equal to the constant scalar times the derivative of the vector function.

  • b) ddu(A+B)=dAdu+dBdu\frac{d}{du}(A+B) = \frac{dA}{du} + \frac{dB}{du} Assuming "AB" in the image refers to the sum A+BA+B, this is the sum rule for vector differentiation. It states that the derivative of the sum of two vector functions A(u)A(u) and B(u)B(u) is the sum of their individual derivatives.

  • c) ddu(A⋅B)=A⋅dBdu+dAdu⋅B\frac{d}{du}(A \cdot B) = A \cdot \frac{dB}{du} + \frac{dA}{du} \cdot B This is the product rule for the scalar (dot) product of two vector functions. It shows how to differentiate the dot product, similar to the scalar product rule, but maintaining the dot product operation.

  • d) ddu(A×B)=A×dBdu+dAdu×B\frac{d}{du}(A \times B) = A \times \frac{dB}{du} + \frac{dA}{du} \times B This is the product rule for the vector (cross) product of two vector functions. It's similar to the scalar product rule, but it's crucial to maintain the original order of the vectors in the cross product due to its non-commutative nature.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp