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Mathematics

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Part 2

Part 2.1· 1 step

Convert 155 g to kg.

  1. Use the conversion factor 1 kg=1000 g1 \text{ kg} = 1000 \text{ g}.

    155 g=1551000 kg155 \text{ g} = \frac{155}{1000} \text{ kg} 155 g=0.155 kg155 \text{ g} = 0.155 \text{ kg}

    The mass in kilograms is 0.155 kg\boxed{\text{0.155 kg}}.

Part 2.2· 2 steps

Determine the profit he will make if he sells a tin of Lucky Star pilchards.

  1. Identify the selling price and cost price for Lucky Star pilchards.

    Cost Price = R14.99
    Selling Price = R17.99

  2. Calculate the profit.

    Profit=Selling Price−Cost Price\text{Profit} = \text{Selling Price} - \text{Cost Price} Profit=R17.99−R14.99\text{Profit} = \text{R}17.99 - \text{R}14.99 Profit=R3.00\text{Profit} = \text{R}3.00

    The profit is R3.00\boxed{\text{R3.00}}.

Part 2.3· 2 steps

He buys a 5 kg Iwisa samp and repacks the samp into 125 g packets. Determine how many packets will be able to get from one pack of 5 kg samp.

  1. Convert the total mass of samp from kg to g.

    5 kg=5×1000 g=5000 g5 \text{ kg} = 5 \times 1000 \text{ g} = 5000 \text{ g}

  2. Divide the total mass by the mass per packet.

    Number of packets=Total massMass per packet\text{Number of packets} = \frac{\text{Total mass}}{\text{Mass per packet}} Number of packets=5000 g125 g\text{Number of packets} = \frac{5000 \text{ g}}{125 \text{ g}} Number of packets=40\text{Number of packets} = 40

    He will be able to get 40 packets\boxed{\text{40 packets}}.

Part 2.4· 3 steps

If the 10 kg Tastic rice is divided into 8 smaller packets. Calculate the selling price of ONE small packet.

  1. Identify the selling price of the 10 kg Tastic rice.

    Selling Price of 10 kg Tastic rice = R192.49

  2. Divide the total selling price by the number of small packets.

    Selling price per small packet=Total selling priceNumber of packets\text{Selling price per small packet} = \frac{\text{Total selling price}}{\text{Number of packets}} Selling price per small packet=R192.498\text{Selling price per small packet} = \frac{\text{R}192.49}{8} Selling price per small packet=R24.06125\text{Selling price per small packet} = \text{R}24.06125

  3. Round to two decimal places for currency.

    Selling price per small packet≈R24.06\text{Selling price per small packet} \approx \text{R}24.06

    The selling price of one small packet is R24.06\boxed{\text{R24.06}}.

Part 3

Part 3.1· 2 steps

How many metres of material will she need to make the above 3 dresses?

  1. Identify the material needed for each dress size.

    6-year-old dress: 3 metres
    7-year-old dress: 4 metres
    10-year-old dress: 5 metres

  2. Sum the material needed for all three dresses.

    Total material=3 m+4 m+5 m\text{Total material} = 3 \text{ m} + 4 \text{ m} + 5 \text{ m} Total material=12 m\text{Total material} = 12 \text{ m}

    She will need 12 metres\boxed{\text{12 metres}} of material.

Part 3.2· 2 steps

What will the material cost for the three dresses?

  1. Use the total material needed from 3.1 and the cost per metre.

    Total material = 12 metres
    Material cost = R120 per metre

  2. Calculate the total material cost.

    Total material cost=Total material×Cost per metre\text{Total material cost} = \text{Total material} \times \text{Cost per metre} Total material cost=12 m×R120/m\text{Total material cost} = 12 \text{ m} \times \text{R}120/\text{m} Total material cost=R1440\text{Total material cost} = \text{R}1440

    The material cost for the three dresses is R1440\boxed{\text{R1440}}.

Part 3.3· 2 steps

Calculate in centimetre the length of the embroidery cotton that Nkgono is going to use when sewing one dress.

  1. Determine the total length of embroidery cotton in metres for one dress.

    She uses 3 rolls of cotton per dress.
    Each roll is 4 metres.

    Total length in metres=3 rolls×4 m/roll\text{Total length in metres} = 3 \text{ rolls} \times 4 \text{ m/roll} Total length in metres=12 m\text{Total length in metres} = 12 \text{ m}

  2. Convert the total length from metres to centimetres.

    1 m=100 cm1 \text{ m} = 100 \text{ cm} Total length in centimetres=12 m×100 cm/m\text{Total length in centimetres} = 12 \text{ m} \times 100 \text{ cm/m} Total length in centimetres=1200 cm\text{Total length in centimetres} = 1200 \text{ cm}

    The length of the embroidery cotton for one dress is 1200 cm\boxed{\text{1200 cm}}.

Part 3.4· 2 steps

Calculate the total amount that she will pay for the embroidery cotton?

This question refers to the embroidery cotton for one dress, based on the context of 3.3 and 3.5.

  1. Identify the cost per roll and the number of rolls used per dress.

    Cost per roll = R15
    Rolls per dress = 3

  2. Calculate the total cost for embroidery cotton for one dress.

    Total embroidery cotton cost=Cost per roll×Number of rolls\text{Total embroidery cotton cost} = \text{Cost per roll} \times \text{Number of rolls} Total embroidery cotton cost=R15/roll×3 rolls\text{Total embroidery cotton cost} = \text{R}15/\text{roll} \times 3 \text{ rolls} Total embroidery cotton cost=R45\text{Total embroidery cotton cost} = \text{R}45

    The total amount she will pay for the embroidery cotton for one dress is R45\boxed{\text{R45}}.

Part 3.5· 3 steps

What is the total cost of a dress for a 10 year old?

  1. Determine the material cost for a 10-year-old dress.

    Material needed for a 10-year-old dress = 5 metres
    Material cost = R120 per metre

    Material cost for 10-year-old dress=5 m×R120/m\text{Material cost for 10-year-old dress} = 5 \text{ m} \times \text{R}120/\text{m} Material cost for 10-year-old dress=R600\text{Material cost for 10-year-old dress} = \text{R}600

  2. Add the cost of the embroidery cotton for one dress (from 3.4).

    Embroidery cotton cost for one dress = R45

  3. Calculate the total cost.

    Total cost of 10-year-old dress=Material cost+Embroidery cotton cost\text{Total cost of 10-year-old dress} = \text{Material cost} + \text{Embroidery cotton cost} Total cost of 10-year-old dress=R600+R45\text{Total cost of 10-year-old dress} = \text{R}600 + \text{R}45 Total cost of 10-year-old dress=R645\text{Total cost of 10-year-old dress} = \text{R}645

    The total cost of a dress for a 10-year-old is R645\boxed{\text{R645}}.

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