What is the greatest number that can divide 36 without leaving a remainder?

The ratio of boys to girls is $2:3$.
Total parts $= 2 + 3 = 5$.

There are 200 learners in total. The girls represent 3 out of 5 parts.
Number of girls $= \frac{3}{5} \times 200$.

Number of girls $= 3 \times \frac{200}{5} = 3 \times 40 = 120$.
The number of girls is $\boxed{\text{120}}$.

Question 9:

Factors of 36 are $1, 2, 3, 4, 6, 9, 12, 18, 36$.

Factors of 54 are $1, 2, 3, 6, 9, 18, 27, 54$.

The common factors are $1, 2, 3, 6, 9, 18$. The greatest among these is 18.
The greatest number that can divide 36 and 54 without leaving a remainder is c) 18.
The answer is $\boxed{\text{18}}$.

Question 10:

$4 \times 1000 = 4000$
$2 \times 100 = 200$
$3 \times 1 = 3$

$4000 + 200 + 3 = 4203$.
The short form is $\boxed{\text{4203}}$.

Question 11:

The numbers are $-14, 13, -12, 12, 4, 5, 0$.

Start with the largest positive numbers, then zero, then the largest (least negative) negative numbers.
$13, 12, 5, 4, 0, -12, -14$.
The numbers in descending order are $\boxed{13, 12, 5, 4, 0, -12, -14}$.

Question 12 A:

The actual distance is $15 \text{ km}$.
$1 \text{ km} = 1000 \text{ m}$
$1 \text{ m} = 100 \text{ cm}$
So, $1 \text{ km} = 1000 \times 100 \text{ cm} = 100,000 \text{ cm}$.
Actual distance $= 15 \times 100,000 \text{ cm} = 1,500,000 \text{ cm}$.

The scale is $1:1,50,000$, which means $1 \text{ unit on map} = 1,50,000 \text{ units in reality}$.
Length on drawing $= \frac{\text{Actual distance}}{\text{Scale factor}}$.
Length on drawing $= \frac{1,500,000 \text{ cm}}{1,50,000}$.

Length on drawing $= 10 \text{ cm}$.
None of the options match $10 \text{ cm}$. Let's recheck the calculation or options.
If the scale is $1:1,50,000$, then map distance = actual distance / 1,50,000.
Map distance $= \frac{15 \text{ km}}{1,50,000} = \frac{15 \times 1000 \text{ m}}{1,50,000} = \frac{15000 \text{ m}}{1,50,000} = \frac{15}{150} \text{ m} = \frac{1}{10} \text{ m} = 0.1 \text{ m}$.
$0.1 \text{ m} = 0.1 \times 100 \text{ cm} = 10 \text{ cm}$.

Let's re-examine the options and the question. It's possible there's a typo in the question or options.
If the question meant 1.5 km, then:
Map distance $= \frac{1.5 \text{ km}}{1,50,000} = \frac{1.5 \times 100,000 \text{ cm}}{1,50,000} = \frac{150,000 \text{ cm}}{1,50,000} = 1 \text{ cm}$.

Let's assume there might be a typo in the scale or the actual distance, or the options.
If the actual distance was $45 \text{ km}$, then map distance $= \frac{45 \text{ km}}{1,50,000} = \frac{45 \times 100,000 \text{ cm}}{1,50,000} = \frac{4,500,000 \text{ cm}}{1,50,000} = 30 \text{ cm}$. This matches option a).
Given the options, it's highly probable that the actual distance was intended to be $45 \text{ km}$ to match option a) $30 \text{ cm}$.
However, based strictly on the given $15 \text{ km}$:
Length on drawing $= \frac{15 \text{ km}}{1,50,000} = \frac{15 \times 1000 \text{ m}}{1,50,000} = \frac{15000 \text{ m}}{1,50,000} = \frac{1}{10} \text{ m} = 0.1 \text{ m}$.
Converting $0.1 \text{ m}$ to centimeters: $0.1 \text{ m} \times 100 \text{ cm/m} = 10 \text{ cm}$.
Since $10 \text{ cm}$ is not an option, and $0.1 \text{ m}$ is not an option, let's check if any option is $0.3 \text{ m}$.
$0.3 \text{ m} = 30 \text{ cm}$. This would imply the actual distance was $45 \text{ km}$.

Given the discrepancy, I will state the answer based on the provided numbers and note the mismatch.
Length on drawing $= \frac{15 \text{ km}}{1,50,000} = \frac{15 \times 100,000 \text{ cm}}{1,50,000} = \frac{1,500,000 \text{ cm}}{1,50,000} = 10 \text{ cm}$.
Since $10 \text{ cm}$ is not among the options, and $0.1 \text{ m}$ is also not an option, there might be an error in the question or options. If we assume the answer should be one of the options, and $30 \text{ cm}$ (option a) is a common answer for such problems, it would imply the actual distance was $45 \text{ km}$.
However, sticking to the given numbers:
Length on drawing $= 10 \text{ cm}$.
As this is not an option, I cannot select one. If forced to choose the closest or most likely intended answer based on typical exam patterns, it's often that $30 \text{ cm}$ (option a) is the answer for a $45 \text{ km}$ distance. Without clarification, I cannot definitively pick an option.

Let's assume the question intended for the answer to be $30 \text{ cm}$ (option a), which would mean the actual distance was $45 \text{ km}$.
If actual distance $= 45 \text{ km}$:
Length on drawing $= \frac{45 \text{ km}}{1,50,000} = \frac{45 \times 100,000 \text{ cm}}{1,50,000} = \frac{4,500,000 \text{ cm}}{1,50,000} = 30 \text{ cm}$.
So, if the actual distance was $45 \text{ km}$, the answer would be a) 30cm.
Given the problem as stated, the calculated answer is $10 \text{ cm}$. Since this is not an option, I cannot provide a definitive option from the list.

Question 12 B:

The circumference $C = 2 \pi r$.

Given radius $r = 10 \text{ cm}$ and $\pi = 3.14$.
$C = 2 \times 3.14 \times 10 \text{ cm}$.

$C = 20 \times 3.14 \text{ cm} = 62.8 \text{ cm}$.
The circumference of the circle is $\boxed{62.8 \text{ cm}}$.

Question 13:

"Six million" means 6,000,000.
"Fourteen thousand" means 14,000.
"Three hundred forty" means 340.

$6,000,000 + 14,000 + 340 = 6,014,340$.
The number in figures is $\boxed{6,014,340}$.