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The length, l cm, of a sheet of paper is 29.7 cm, correct to the nearest millimeter. Complete the statement about the value of l.

Mathematics

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8. The length, ll cm, of a sheet of paper is 29.7 cm, correct to the nearest millimeter. Complete the statement about the value of ll.

To find the lower and upper bounds when a measurement is given to the nearest millimeter (which is 0.1 cm), we take half of the precision (0.1 cm / 2 = 0.05 cm).

  1. Calculate the lower bound.

    Lower bound = 29.7 cm−0.05 cm=29.65 cm29.7 \text{ cm} - 0.05 \text{ cm} = 29.65 \text{ cm}

  2. Calculate the upper bound.

    Upper bound = 29.7 cm+0.05 cm=29.75 cm29.7 \text{ cm} + 0.05 \text{ cm} = 29.75 \text{ cm}

    The value of ll is between the lower bound (inclusive) and the upper bound (exclusive).

    29.65≤l<29.75\boxed{29.65 \le l < 29.75}

    9. Lucia invests $5000 at a rate of 4.5% per year simple interest. Calculate the value of her investment after 7 years.

  3. Calculate the simple interest earned.

    The formula for simple interest is I=P×R×TI = P \times R \times T, where PP is the principal, RR is the annual interest rate, and TT is the time in years. I=$5000×0.045×7I = \$5000 \times 0.045 \times 7 I=$1575I = \$1575

  4. Calculate the total value of the investment.

    Total value = Principal + Interest Total value=$5000+$1575\text{Total value} = \$5000 + \$1575 Total value=$6575\text{Total value} = \$6575 The value of her investment after 7 years is \boxed{\6575}$.

    10. Rectangle A measures 3 cm by 8 cm. Five rectangles congruent to A are joined to make a shape. Work out the perimeter of the shape.

    Each rectangle has dimensions: width = 3 cm, length = 8 cm.
    Let's trace the outer edges of the combined shape shown in the diagram.

  5. Identify and sum the horizontal segments of the perimeter.

    • There are three horizontal segments at the top of the shape: 3 cm (left), 8 cm (middle), 3 cm (right).
    • There are three horizontal segments at the bottom of the shape: 3 cm (left), 8 cm (middle), 3 cm (right). Total horizontal perimeter = (3 cm+8 cm+3 cm)×2(3 \text{ cm} + 8 \text{ cm} + 3 \text{ cm}) \times 2 Total horizontal perimeter = 14 cm×2=28 cm14 \text{ cm} \times 2 = 28 \text{ cm}.
  6. Identify and sum the vertical segments of the perimeter.

    • There are two outer vertical segments on the far left: 8 cm (top) + 8 cm (bottom).
    • There are two outer vertical segments on the far right: 8 cm (top) + 8 cm (bottom).
    • There are four inner vertical segments where the central horizontal rectangle connects to the vertical rectangles. Each of these segments is 3 cm (the width of a rectangle). Total vertical perimeter = (8 cm×4)+(3 cm×4)(8 \text{ cm} \times 4) + (3 \text{ cm} \times 4) Total vertical perimeter = 32 cm+12 cm=44 cm32 \text{ cm} + 12 \text{ cm} = 44 \text{ cm}.
  7. Calculate the total perimeter.

    Total perimeter = Total horizontal perimeter + Total vertical perimeter
    Total perimeter = 28 cm+44 cm28 \text{ cm} + 44 \text{ cm}
    Total perimeter = 72 cm72 \text{ cm}.
    The perimeter of the shape is 72 cm\boxed{72 \text{ cm}}.

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