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The lengths of the sides of a cuboid are y+4, y+2, 2y+1, and y+1. Find the value of y and the volume of the cuboid.

Mathematics

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Answers

2 parts
a

y=0y = 0

b

8 cm38 \text{ cm}^3

Step-by-step solution

6 steps

Here's how to solve the problem:

Part a· 3 steps

Find the value of yy.

  1. Identify the dimensions of the cuboid.

    From the diagram, the length is y+4 cmy+4 \text{ cm}, the height is y+2 cmy+2 \text{ cm}.
    The width (or depth) of the cuboid is labeled with two expressions: 2y+1 cm2y+1 \text{ cm} and y+1 cmy+1 \text{ cm}. Since these represent the same physical dimension, they must be equal.

  2. Set up an equation using the expressions for the width.

    2y+1=y+12y+1 = y+1
  3. Solve the equation for yy.

    Subtract yy from both sides:

    2y−y+1=12y - y + 1 = 1 y+1=1y + 1 = 1

    Subtract 1 from both sides:

    y=1−1y = 1 - 1 y=0y = 0

    The value of yy is:

    y=0\boxed{y = 0}

Part b

8 cm38 \text{ cm}^3

Calculate its volume.

  1. Determine the actual dimensions of the cuboid using y=0y=0.

    Length (ll) =y+4=0+4=4 cm= y+4 = 0+4 = 4 \text{ cm}
    Width (ww) =2y+1=2(0)+1=1 cm= 2y+1 = 2(0)+1 = 1 \text{ cm} (or y+1=0+1=1 cmy+1 = 0+1 = 1 \text{ cm})
    Height (hh) =y+2=0+2=2 cm= y+2 = 0+2 = 2 \text{ cm}

  2. State the formula for the volume of a cuboid.

    V=l×w×hV = l \times w \times h
  3. Substitute the dimensions into the formula and calculate the volume.

    V=4 cm×1 cm×2 cmV = 4 \text{ cm} \times 1 \text{ cm} \times 2 \text{ cm} V=8 cm3V = 8 \text{ cm}^3

    The volume of the cuboid is:

    8 cm3\boxed{8 \text{ cm}^3}
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