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What is the perimeter of a rectangle with length 7/2 and width 5/3? Calculate the area as well.

Mathematics

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Step 1: Solve Question 1(c).
The shape is a rectangle with length l=72l = \frac{7}{2} and width w=53w = \frac{5}{3}.

  • Perimeter: The formula for the perimeter of a rectangle is P=2(l+w)P = 2(l+w). P=2(72+53)P = 2\left(\frac{7}{2} + \frac{5}{3}\right) Find a common denominator for the fractions inside the parenthesis: P=2(7×32×3+5×23×2)P = 2\left(\frac{7 \times 3}{2 \times 3} + \frac{5 \times 2}{3 \times 2}\right)
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