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What is the place value of 7 in 3.487?

Mathematics

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2. What is the place value of 7 in 3.487?

  1. Identify the position of the digit 7 in the decimal number 3.487.

    The number is 3.487.

    • 3 is in the ones place.
    • 4 is in the tenths place (410\frac{4}{10}).
    • 8 is in the hundredths place (8100\frac{8}{100}).
    • 7 is in the thousandths place (71000\frac{7}{1000}).
  2. State the place value.

    The place value of 7 is 71000\frac{7}{1000}.
    The correct option is A.

    3. Find the highest common factor (H.C.F) of 4, 6 and 12.

  3. List the factors for each number.

    Factors of 4: 1, 2, 4
    Factors of 6: 1, 2, 3, 6
    Factors of 12: 1, 2, 3, 4, 6, 12

  4. Identify the common factors.

    The common factors are 1 and 2.

  5. Determine the highest common factor.

    The highest common factor (H.C.F.) is 2.
    The correct option is A.

    4. Which of the following is not a multiple of 3?

  6. Check each option to see if it is divisible by 3.

    A. 6÷3=26 \div 3 = 2 (6 is a multiple of 3)
    B. 9÷3=39 \div 3 = 3 (9 is a multiple of 3)
    C. 16÷3=516 \div 3 = 5 with a remainder of 1 (16 is not a multiple of 3)
    D. 12÷3=412 \div 3 = 4 (12 is a multiple of 3)
    E. 24÷3=824 \div 3 = 8 (24 is a multiple of 3)

  7. Identify the number that is not a multiple of 3.

    16 is not a multiple of 3.
    The correct option is C.

    5. Find the square root of 32×423^2 \times 4^2.

  8. Calculate the value of 32×423^2 \times 4^2.

    32=93^2 = 9 42=164^2 = 16 32×42=9×16=1443^2 \times 4^2 = 9 \times 16 = 144
  9. Find the square root of the result.

    144=12\sqrt{144} = 12

    The correct option is B.

    6. Find the difference between the sum of 128, 857, 155 and 140.

  10. Interpret the question.

    Given the options, this question is best interpreted as finding the difference between the sum of the first three numbers and the last number.
    Sum of 128, 857, and 155:

    128+857+155=1140128 + 857 + 155 = 1140
  11. Find the difference between this sum and 140.

    1140−140=10001140 - 140 = 1000

    The correct option is B.

    7. Divide the L.C.M. of 9, 12 and 18 by their H.C.F.

  12. Find the Least Common Multiple (L.C.M.) of 9, 12, and 18.

    Prime factorization:
    9=329 = 3^2
    12=22×312 = 2^2 \times 3
    18=2×3218 = 2 \times 3^2
    L.C.M. is the product of the highest powers of all prime factors: 22×32=4×9=362^2 \times 3^2 = 4 \times 9 = 36.

  13. Find the Highest Common Factor (H.C.F.) of 9, 12, and 18.

    H.C.F. is the product of the lowest powers of common prime factors: 31=33^1 = 3.

  14. Divide the L.C.M.

    by the H.C.F.

    L.C.M.H.C.F.=363=12\frac{\text{L.C.M.}}{\text{H.C.F.}} = \frac{36}{3} = 12

    The correct option is D.

    8. Express 144256\frac{144}{256} in its lowest term.

  15. Find the greatest common divisor (GCD) of the numerator (144) and the denominator (256).

    We can simplify by dividing by common factors repeatedly.

    144256÷22=72128\frac{144}{256} \div \frac{2}{2} = \frac{72}{128} 72128÷22=3664\frac{72}{128} \div \frac{2}{2} = \frac{36}{64} 3664÷22=1832\frac{36}{64} \div \frac{2}{2} = \frac{18}{32} 1832÷22=916\frac{18}{32} \div \frac{2}{2} = \frac{9}{16}
  16. Confirm that the fraction is in its lowest term.

    The numbers 9 and 16 have no common factors other than 1.
    The fraction in its lowest term is 916\frac{9}{16}.
    The correct option is A.

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