This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 1: Answer question 2.1.1. The meter number is explicitly stated on the till slip under "Meter:". The meter number is 07032985769. Step 2: Answer question 2.1.2. The till slip shows the following breakdown: Electricity: R1 130,43 VAT 15%: B TOTAL: R1 300,00 To find the missing value B, which represents the VAT, we subtract the Electricity amount from the Total amount. B = Total - Electricity B = R1\,300.00 - R1\,130.43 B = R169.57 Step 3: Answer question 2.1.3 by calculating the cost for Block 1. The total electricity amount Mieecke purchased (excluding VAT) is R1 130,43. The tariff table is: • Block 1: 0-350 kWh at R2.19/kWh • Block 2: More than 350 kWh at R2.91/kWh First, calculate the cost for the maximum consumption in Block 1: Cost for Block 1 = 350 kWh × R2.19/kWh Cost for Block 1 = R766.50 Step 4: Calculate the remaining cost and the kWh units in Block 2. Since the total electricity cost (R1 130,43) is greater than the cost for Block 1 (R766.50), Mieecke purchased units in Block 2. Calculate the remaining cost that falls into Block 2: Remaining cost = Total electricity cost - Cost for Block 1 Remaining cost = R1\,130.43 - R766.50 Remaining cost = R363.93 Now, calculate the number of kWh units purchased in Block 2 using the tariff for Block 2: Units in Block 2 = Remaining costTariff for Block 2 Units in Block 2 = R363.93R2.91/kWh Units in Block 2 = 125.06185... kWh Step 5: Calculate the total number of kWh units purchased. Add the units from Block 1 and Block 2: Total kWh units = Units in Block 1 + Units in Block 2 Total kWh units = 350 kWh + 125.06185... kWh Total kWh units = 475.06185... kWh Rounding to two decimal places: Total kWh units = 475.06 kWh 3 done, 2 left today. You're making progress.