What is the temperature change from 7°C to -13°C? Evaluate 2/3(2 1/5 - 1 1/2) + 1 1/5 * 3/4 + 1 2/5

Initial temperature = $7^\circ\text{C}$
Final temperature = $-13^\circ\text{C}$

The drop in temperature is the initial temperature minus the final temperature.

The drop in temperature was $\boxed{\text{A. } 20^\circ\text{C}}$.

2.

Find a common denominator for $\frac{11}{5}$ and $\frac{3}{2}$, which is 10.

The possible answer is $\boxed{\text{D. } 2\frac{23}{30}}$.

3.

The first non-zero digit is 4. So, we move the decimal point after 4.

The decimal point moved 4 places to the right.

The area expressed in standard form is $\boxed{\text{B. } 4.61 \times 10^{-4}}$.

4.

Area ($A$) = $12.96 \text{ m}^2$

For a square, $A = s^2$. So, $s = \sqrt{A}$.

The perimeter ($P$) of a square is $4 \times s$.

The perimeter of the farm is $\boxed{\text{A. } 14.4 \text{ m}}$.

5.

Let the width be $X$ meters.
The length is 5 m more than its width, so Length = $(X + 5)$ meters.

Perimeter ($P$) = $2(\text{Length} + \text{Width})$

This equation represents the given information.
The correct option is $\boxed{\text{C. } 4X + 10 = 52}$.

6.

The number line shows a closed circle at 9. This means 9 is included in the solution.
The arrow points to the left from 9. This means all numbers less than 9 are included.

The values are less than or equal to 9.

The inequality that represents the above information is $\boxed{\text{A. } X \le 9}$.

7.

From the diagram, the floor is a rectangle with length $15 \text{ m}$ and width $10 \text{ m}$.

Area of floor = Length $\times$ Width

The carpet leaves a uniform margin of $1 \text{ m}$ from the wall on all sides.
Carpet length = Floor length - $2 \times \text{margin}$

Carpet width = Floor width - $2 \times \text{margin}$

Area of carpet = Carpet length $\times$ Carpet width

Area not covered = Area of floor - Area of carpet

There seems to be a mismatch with the provided options (A. 170m², B. 144cm², C. 50m², D. 120cm²). Let me re-check the question and my calculations.
The question asks for the area of the space not covered by the carpet. My calculation is $46 \text{ m}^2$. None of the options match this.
Let's re-examine the image for any misinterpretation.
The diagram shows the floor as 15m by 10m. The carpet is placed with a 1m margin.
Floor area = 15 * 10 = 150 m^2.
Carpet length = 15 - 1 - 1 = 13m.
Carpet width = 10 - 1 - 1 = 8m.
Carpet area = 13 * 8 = 104 m^2.
Area not covered = 150 - 104 = 46 m^2.

It's possible there's an error in the question's options or the diagram's labels. However, based on the information given, $46 \text{ m}^2$ is the correct answer. Since I must select from the given options, and none of them are $46 \text{ m}^2$, I cannot provide a definitive answer from the options. I will state the calculated answer.

The area of the space not covered by the carpet is $\boxed{46 \text{ m}^2}$.
(Note: This answer is not among the provided options.)