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The total wage, W, earned by a worker in a week is given by the formula W = 15h + 50, where W is the total wage in Ghana cedis and h is the number of hours worked. Find the wage for 20 hours, 35 hours

Mathematics

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Question 3
The total wage, WW, earned by a worker in a week is given by the formula W=15h+50W = 15h + 50, where WW is the total wage in Ghana cedis and hh is the number of hours worked.

  • (i) Find the wage for 20 hours.
  1. Substitute h=20h = 20 into the formula.

    $$
    W = 15(20) + 50
    $$
    
  2. Calculate the wage.

    $$
    W = 300 + 50
    $$
    $$
    W = 350
    $$
    The wage for 20 hours is $\boxed{\text{GHC 350.00}}$.
    
    • (ii) If the worker did 35 hours of work, what would be the wage?
  3. Substitute h=35h = 35 into the formula.

    $$
    W = 15(35) + 50
    $$
    
  4. Calculate the wage.

    $$
    W = 525 + 50
    $$
    $$
    W = 575
    $$
    The wage for 35 hours of work is $\boxed{\text{GHC 575.00}}$.
    
    • (iii) How long will it take for the wage to reach GHC 500.00?
  5. Set W=500W = 500 in the formula.

    $$
    500 = 15h + 50
    $$
    
  6. Subtract 50 from both sides.

    $$
    500 - 50 = 15h
    $$
    $$
    450 = 15h
    $$
    
  7. Divide by 15 to solve for hh.

    $$
    h = \frac{450}{15}
    $$
    $$
    h = 30
    $$
    It will take $\boxed{\text{30 hours}}$ for the wage to reach GHC 500.00.
    

    Vector Problem
    Given p=(6−2)\mathbf{p} = \begin{pmatrix} 6 \\ -2 \end{pmatrix} and q=(−43)\mathbf{q} = \begin{pmatrix} -4 \\ 3 \end{pmatrix}, find:

    • (i) 2p−q2\mathbf{p} - \mathbf{q}
  8. Calculate 2p2\mathbf{p}.

    $$
    2\mathbf{p} = 2 \begin{pmatrix} 6 \\ -2 \end{pmatrix} = \begin{pmatrix} 2 \times 6 \\ 2 \times -2 \end{pmatrix} = \begin{pmatrix} 12 \\ -4 \end{pmatrix}
    $$
    
  9. Subtract q\mathbf{q} from 2p2\mathbf{p}.

    $$
    2\mathbf{p} - \mathbf{q} = \begin{pmatrix} 12 \\ -4 \end{pmatrix} - \begin{pmatrix} -4 \\ 3 \end{pmatrix}
    $$
    $$
    2\mathbf{p} - \mathbf{q} = \begin{pmatrix} 12 - (-4) \\ -4 - 3 \end{pmatrix}
    $$
    $$
    2\mathbf{p} - \mathbf{q} = \begin{pmatrix} 12 + 4 \\ -7 \end{pmatrix}
    $$
    $$
    2\mathbf{p} - \mathbf{q} = \boxed{\begin{pmatrix} 16 \\ -7 \end{pmatrix}}
    $$
    
    • (ii) the magnitude of p\mathbf{p}.
  10. Use the formula for the magnitude of a vector v=(xy)\mathbf{v} = \begin{pmatrix} x \\ y \end{pmatrix}, which is ∣∣v∣∣=x2+y2||\mathbf{v}|| = \sqrt{x^2 + y^2}.

    For $\mathbf{p} = \begin{pmatrix} 6 \\ -2 \end{pmatrix}$, $x=6$ and $y=-2$.
    $$
    ||\mathbf{p}|| = \sqrt{6^2 + (-2)^2}
    $$
    
  11. Calculate the squares.

    $$
    ||\mathbf{p}|| = \sqrt{36 + 4}
    $$
    
  12. Add and find the square root.

    $$
    ||\mathbf{p}|| = \sqrt{40}
    $$
    $$
    ||\mathbf{p}|| = \sqrt{4 \times 10} = 2\sqrt{10}
    $$
    The magnitude of $\mathbf{p}$ is $\boxed{2\sqrt{10}}$.
    

    The image also shows a table with "Packages (x)" and "Customers (f)", but the question related to this table is not visible.

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