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The user needs help solving 3 math problems: one on simultaneous equations, one on average speed, and one on map scale and area.

Mathematics

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1. Solve the following simultaneous equation using elimination:

x+y=10(1)x + y = 10 \quad (1) x−y=2(2)x - y = 2 \quad (2)
  1. Add equation (1) and equation (2) to eliminate yy.

    (x+y)+(x−y)=10+2(x + y) + (x - y) = 10 + 2 2x=122x = 12
  2. Solve for xx.

    2x2=122\frac{2x}{2} = \frac{12}{2} x=6x = 6
  3. Substitute the value of xx into equation (1) to find yy.

    6+y=106 + y = 10 y=10−6y = 10 - 6 y=4y = 4

    The solution is x=6,y=4\boxed{x=6, y=4}.

    2. In a shooting range, the target is placed 320 m away from the shooting point. If the bullet took 2122\frac{1}{2} seconds to hit the target, what was the average speed of the bullet?

  4. Identify the given values.

    Distance (dd) = 320 m
    Time (tt) = 2122\frac{1}{2} s = 2.5 s

  5. Use the formula for average speed.

    Average Speed=DistanceTime\text{Average Speed} = \frac{\text{Distance}}{\text{Time}} Average Speed=320 m2.5 s\text{Average Speed} = \frac{320 \text{ m}}{2.5 \text{ s}}
  6. Calculate the average speed.

    Average Speed=128 m/s\text{Average Speed} = 128 \text{ m/s}

    The average speed of the bullet was 128 m/s\boxed{128 \text{ m/s}}.

    3. On a given map with scale of 1:600, a rectangular shape was measuring 6 cm by 2.5 cm. Find the actual area of the rectangular shape in square metres.

  7. Convert the map dimensions to actual dimensions using the scale 1:600.

    Actual length = Map length ×\times Scale factor
    Actual length = 6 cm×600=3600 cm6 \text{ cm} \times 600 = 3600 \text{ cm}
    Actual width = Map width ×\times Scale factor
    Actual width = 2.5 cm×600=1500 cm2.5 \text{ cm} \times 600 = 1500 \text{ cm}

  8. Convert the actual dimensions from centimeters to meters.

    (1 m = 100 cm)
    Actual length in meters = 3600 cm100 cm/m=36 m\frac{3600 \text{ cm}}{100 \text{ cm/m}} = 36 \text{ m}
    Actual width in meters = 1500 cm100 cm/m=15 m\frac{1500 \text{ cm}}{100 \text{ cm/m}} = 15 \text{ m}

  9. Calculate the actual area in square meters.

    Actual Area=Actual length×Actual width\text{Actual Area} = \text{Actual length} \times \text{Actual width} Actual Area=36 m×15 m\text{Actual Area} = 36 \text{ m} \times 15 \text{ m} Actual Area=540 m2\text{Actual Area} = 540 \text{ m}^2

    The actual area of the rectangular shape is 540 m2\boxed{540 \text{ m}^2}.

    4. Solve 2x−63=x−44\frac{2x - 6}{3} = \frac{x - 4}{4}

  10. Cross-multiply to eliminate the denominators.

    4(2x−6)=3(x−4)4(2x - 6) = 3(x - 4)
  11. Distribute the numbers on both sides of the equation.

    8x−24=3x−128x - 24 = 3x - 12
  12. Gather xx terms on one side and constant terms on the other side.

    8x−3x=−12+248x - 3x = -12 + 24 5x=125x = 12
  13. Solve for xx.

    x=125x = \frac{12}{5} x=2.4x = 2.4

    The solution is x=125 or 2.4\boxed{x = \frac{12}{5} \text{ or } 2.4}.

    5. Factorise 4y−1444y - 144

  14. Find the greatest common factor (GCF) of the terms $4y$ and 144.

    The GCF of 4 and 144 is 4.

  15. Factor out the GCF from the expression.

    4y−144=4(y−36)4y - 144 = 4(y - 36)

    The factorised expression is 4(y−36)\boxed{4(y - 36)}.

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