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The value of the determinant of the matrix (S -2) is 7. a) Find the value of x b) Hence write down the inverse of the matrix -4 x

Mathematics

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2 parts
a
3
b

(37274757)\begin{pmatrix} \frac{3}{7} & \frac{2}{7} \\ \frac{4}{7} & \frac{5}{7} \end{pmatrix}

Step-by-step solution

7 steps

Part a· 3 steps

To find the value of xx, we use the formula for the determinant of a 2×22 \times 2 matrix.

Given the matrix A=(5−2−4x)A = \begin{pmatrix} 5 & -2 \\ -4 & x \end{pmatrix} and its determinant is 7.

  1. Write down the formula for the determinant of a 2×22 \times 2 matrix.

    For a matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix}, the determinant is ad−bcad - bc.

  2. Substitute the values from the given matrix into the determinant formula and set it equal to 7.

    (5)(x)−(−2)(−4)=7(5)(x) - (-2)(-4) = 7
  3. Simplify and solve for xx.

    5x−8=75x - 8 = 7 5x=7+85x = 7 + 8 5x=155x = 15 x=155x = \frac{15}{5} x=3x = \boxed{3}

Part b

(37274757)\begin{pmatrix} \frac{3}{7} & \frac{2}{7} \\ \frac{4}{7} & \frac{5}{7} \end{pmatrix}

To find the inverse of the matrix, we first substitute the value of xx found in part (a) into the matrix.

  1. Write the matrix with the value of xx.

    The matrix is now A=(5−2−43)A = \begin{pmatrix} 5 & -2 \\ -4 & 3 \end{pmatrix}.
    The determinant is given as 7.

  2. Write down the formula for the inverse of a 2×22 \times 2 matrix.

    For a matrix A=(abcd)A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}, the inverse is A−1=1det⁡(A)(d−b−ca)A^{-1} = \frac{1}{\det(A)} \begin{pmatrix} d & -b \\ -c & a \end{pmatrix}.

  3. Substitute the values from the matrix and its determinant into the inverse formula.

    Here, a=5a=5, b=−2b=-2, c=−4c=-4, d=3d=3, and det⁡(A)=7\det(A)=7.

    A−1=17(3−(−2)−(−4)5)A^{-1} = \frac{1}{7} \begin{pmatrix} 3 & -(-2) \\ -(-4) & 5 \end{pmatrix}
  4. Simplify the matrix.

    A−1=17(3245)A^{-1} = \frac{1}{7} \begin{pmatrix} 3 & 2 \\ 4 & 5 \end{pmatrix} A−1=(37274757)A^{-1} = \boxed{\begin{pmatrix} \frac{3}{7} & \frac{2}{7} \\ \frac{4}{7} & \frac{5}{7} \end{pmatrix}}
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