Solve this x4+35=3x22

The given equation is interpreted as $x^4 + 35 = 3x^2 - 2$.
Rearrange the terms to form a standard quartic equation:

$$x^4 - 3x^2 + 35 + 2 = 0$$ $$x^4 - 3x^2 + 37 = 0$$

Let $y = x^2$. The equation becomes:

$$y^2 - 3y + 37 = 0$$