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To determine the value of t in the given equation, we will first find a common denominator to clear the fractions.

Mathematics

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Answer

-15

Step-by-step solution

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To determine the value of tt in the given equation, we will first find a common denominator to clear the fractions.

The equation is:

17+2t3=15t−321+1\frac{1}{7} + \frac{2t}{3} = \frac{15t - 3}{21} + 1
  1. Find the least common multiple (LCM) of the denominators 7, 3, and 21.

    The LCM of 7, 3, and 21 is 21.

  2. Multiply every term in the equation by the LCM (21) to eliminate the denominators.

    21(17)+21(2t3)=21(15t−321)+21(1)21 \left( \frac{1}{7} \right) + 21 \left( \frac{2t}{3} \right) = 21 \left( \frac{15t - 3}{21} \right) + 21 (1)
  3. Simplify each term.

    217+42t3=(15t−3)+21\frac{21}{7} + \frac{42t}{3} = (15t - 3) + 21 3+14t=15t−3+213 + 14t = 15t - 3 + 21
  4. Combine the constant terms on the right side of the equation.

    3+14t=15t+183 + 14t = 15t + 18
  5. Isolate the terms with tt on one side and the constant terms on the other side.

    Subtract 14t14t from both sides:

    3=15t−14t+183 = 15t - 14t + 18 3=t+183 = t + 18

    Subtract 18 from both sides:

    3−18=t3 - 18 = t −15=t-15 = t

    The value of tt is:

    −15-15
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