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Two chords AB and CD intersect internally at X. Given that AX = 10cm, XB = 8cm and CD = 21cm, determine the length XD
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Step-by-step solution
11 steps14. Determine the length XD
Apply the Intersecting Chords Theorem.
When two chords AB and CD intersect internally at a point X, the product of the segments of one chord equals the product of the segments of the other chord.
Given , , and .
Let . Then .Substitute the values into the theorem and form a quadratic equation.
Rearrange the equation into standard quadratic form :
Solve the quadratic equation for .
We can factor the quadratic equation. We need two numbers that multiply to 80 and add up to -21. These numbers are -5 and -16.
This gives two possible values for :
State the possible lengths for XD.
Both values are positive and physically possible lengths.
If , then .
If , then .
Both solutions satisfy the theorem ( and ).The length XD can be either or .
15. Calculate the area bounded by the curve , the lines and the x-axis.
Set up the definite integral for the area.
The area bounded by the curve , the x-axis, and the lines and is given by .
For in the interval , the function is positive, so the area is directly given by the integral.Integrate the function.
Evaluate the definite integral using the limits of integration.
The area is .
16. Determine the coordinate of point A.
Write down the given information in vector form.
Point P has coordinates , so its position vector is .
Point P divides line AB internally in the ratio 4:1, meaning . So, and .
The position vector of point B is .
Let the position vector of point A be .Apply the section formula for internal division.
The formula for a point P dividing a line segment AB in the ratio is:
Substitute the known values:
Solve for the position vector .
Multiply both sides by 5:
Isolate :
State the coordinate of point A.
The position vector corresponds to the coordinate .
The coordinate of point A is .
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