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Two Customer Service agents in a bank work such that the first one takes an average of 5 minutes while the second takes an average of 8 minutes to serve a client. The counters are opened at 8:00 am. When the agents begin serving clients - At what time will they complete serving 182 clients?

Mathematics

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Answer

2424.50 m\text{2424.50 m}

Step-by-step solution

4 steps
  1. Chora mchoro na ueleze vigezo.

    Hebu TT iwe kilele cha mlima, na BB iwe chini ya mlima kwenye ardhi tambarare. Pointi VV na PP ziko kwenye ardhi tambarare, na PP iko karibu na BB kuliko VV.

    • Umbali kati ya VV na PP ni 2000 m.
    • Pembe ya mwinuko kutoka VV hadi TT ni ∠TVB=22∘\angle TVB = 22^\circ.
    • Pembe ya mwinuko kutoka PP hadi TT ni ∠TPB=40∘\angle TPB = 40^\circ. Tunahitaji kupata umbali mfupi zaidi kutoka PP hadi TT, ambao ni urefu wa TPTP.
  2. Tambua pembe za pembetatu △TPV\triangle TPV.

    • Pembe ∠TVP=22∘\angle TVP = 22^\circ (pembe ya mwinuko kutoka VV).
    • Pembe ∠TPB=40∘\angle TPB = 40^\circ (pembe ya mwinuko kutoka PP).
    • Kwa kuwa ∠TPB\angle TPB na ∠TPV\angle TPV ziko kwenye mstari ulionyooka, ∠TPV=180∘−∠TPB=180∘−40∘=140∘\angle TPV = 180^\circ - \angle TPB = 180^\circ - 40^\circ = 140^\circ.
    • Jumla ya pembe katika pembetatu ni 180∘180^\circ. Hivyo, pembe ∠VTP=180∘−∠TVP−∠TPV=180∘−22∘−140∘=18∘\angle VTP = 180^\circ - \angle TVP - \angle TPV = 180^\circ - 22^\circ - 140^\circ = 18^\circ.
  3. Tumia Kanuni ya Sine katika pembetatu △TPV\triangle TPV.

    Kanuni ya Sine inasema kwamba kwa pembetatu yoyote, uwiano wa urefu wa upande kwa sine ya pembe inayokabili upande huo ni sawa kwa pande zote.
    Tunataka kupata TPTP. Tunajua VP=2000VP = 2000 m.

    TPsin⁡(∠TVP)=VPsin⁡(∠VTP)\frac{TP}{\sin(\angle TVP)} = \frac{VP}{\sin(\angle VTP)}

    Badilisha thamani zinazojulikana:

    TPsin⁡(22∘)=2000sin⁡(18∘)\frac{TP}{\sin(22^\circ)} = \frac{2000}{\sin(18^\circ)}
  4. Tatua kwa TPTP.

    Ili kupata TPTP, zidisha pande zote mbili kwa sin⁡(22∘)\sin(22^\circ):

    TP=2000×sin⁡(22∘)sin⁡(18∘)TP = \frac{2000 \times \sin(22^\circ)}{\sin(18^\circ)}

    Tumia thamani za sine:
    sin⁡(22∘)≈0.374606\sin(22^\circ) \approx 0.374606
    sin⁡(18∘)≈0.309017\sin(18^\circ) \approx 0.309017

    TP=2000×0.3746060.309017TP = \frac{2000 \times 0.374606}{0.309017} TP=749.2120.309017TP = \frac{749.212}{0.309017} TP≈2424.50 mTP \approx 2424.50 \text{ m}

    Umbali mfupi zaidi kutoka pointi P hadi kilele cha mlima ni:

    2424.50 m\text{2424.50 m}
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