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Understand the relationship between the area of an object, the area of its image, and the determinant of the transformation matrix.

Mathematics

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Answer

−2 or 4-2 \text{ or } 4

Step-by-step solution

6 steps
  1. Understand the relationship between the area of an object, the area of its image, and the determinant of the transformation matrix.

    The area of the image (AimageA_{image}) is related to the area of the object (AobjectA_{object}) by the absolute value of the determinant of the transformation matrix (MM).

    Aimage=∣det⁡(M)∣×AobjectA_{image} = |\det(M)| \times A_{object}
  2. Identify the given values.

    Area of object (AobjectA_{object}) = 9 cm29 \text{ cm}^2
    Area of image (AimageA_{image}) = 54 cm254 \text{ cm}^2
    Transformation matrix (MM) = [2x21]\begin{bmatrix} 2 & x \\ 2 & 1 \end{bmatrix}

  3. Calculate the determinant of the transformation matrix.

    For a 2×22 \times 2 matrix [abcd]\begin{bmatrix} a & b \\ c & d \end{bmatrix}, the determinant is ad−bcad - bc.

    det⁡(M)=(2)(1)−(x)(2)=2−2x\det(M) = (2)(1) - (x)(2) = 2 - 2x
  4. Substitute the values into the area relationship formula.

    54=∣2−2x∣×954 = |2 - 2x| \times 9
  5. Solve for ∣2−2x∣|2 - 2x|.

    Divide both sides by 9:

    549=∣2−2x∣\frac{54}{9} = |2 - 2x| 6=∣2−2x∣6 = |2 - 2x|
  6. Solve for xx.

    The equation ∣2−2x∣=6|2 - 2x| = 6 implies two possibilities:

    • Case 1: 2−2x=62 - 2x = 6 −2x=6−2-2x = 6 - 2 −2x=4-2x = 4 x=4−2x = \frac{4}{-2} x=−2x = -2
    • Case 2: 2−2x=−62 - 2x = -6 −2x=−6−2-2x = -6 - 2 −2x=−8-2x = -8 x=−8−2x = \frac{-8}{-2} x=4x = 4

    Both values of xx satisfy the given conditions.

    The value of xx can be −2 or 4\boxed{-2 \text{ or } 4}.

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