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Subtract using standard algorithm. 73 - 46 = , 92 - 38 = , 88 - 49 = , 97 - 58 = , 84 - 57 = , 69 - 27 = , 75 - 36 = , 61 - 24 = ___

Mathematics

ScanSolve AI Answer

Step-by-step solution

16 steps

73 - 46:

  1. Units place.

    Since 3<63 < 6, borrow 1 from the tens place (7 becomes 6). Now units: 13−6=713 - 6 = 7.

  2. Tens place.

    6−4=26 - 4 = 2.

    73 - 46 = 27

    27\boxed{27}

    84 - 57:

  3. Units place.

    Since 4<74 < 7, borrow 1 from the tens place (8 becomes 7). Now units: 14−7=714 - 7 = 7.

  4. Tens place.

    7−5=27 - 5 = 2.

    84 - 57 = 27

    27\boxed{27}

    92 - 38:

  5. Units place.

    Since 2<82 < 8, borrow 1 from the tens place (9 becomes 8). Now units: 12−8=412 - 8 = 4.

  6. Tens place.

    8−3=58 - 3 = 5.

    92 - 38 = 54

    54\boxed{54}

    69 - 27:

  7. Units place.

    9−7=29 - 7 = 2.

  8. Tens place.

    6−2=46 - 2 = 4.

    69 - 27 = 42

    42\boxed{42}

    88 - 49:

  9. Units place.

    Since 8<98 < 9, borrow 1 from the tens place (8 becomes 7). Now units: 18−9=918 - 9 = 9.

  10. Tens place.

    7−4=37 - 4 = 3.

    88 - 49 = 39

    39\boxed{39}

    75 - 30:

  11. Units place.

    5−0=55 - 0 = 5.

  12. Tens place.

    7−3=47 - 3 = 4.

    75 - 30 = 45

    45\boxed{45}

    97 - 58:

  13. Units place.

    Since 7<87 < 8, borrow 1 from the tens place (9 becomes 8). Now units: 17−8=917 - 8 = 9.

  14. Tens place.

    8−5=38 - 5 = 3.

    97 - 58 = 39

    39\boxed{39}

    61 - 24:

  15. Units place.

    Since 1<41 < 4, borrow 1 from the tens place (6 becomes 5). Now units: 11−4=711 - 4 = 7.

  16. Tens place.

    5−2=35 - 2 = 3.

    61 - 24 = 37

    37\boxed{37}
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