Subtract using standard algorithm. 73 - 46 = , 92 - 38 = , 88 - 49 = , 97 - 58 = , 84 - 57 = , 69 - 27 = , 75 - 36 = , 61 - 24 =

73 - 46:

Step 1: Units place. Since $3 < 6$, borrow 1 from the tens place ($7$ becomes $6$). Now units: $13 - 6 = 7$.

Step 2: Tens place. $6 - 4 = 2$.

73 - 46 = 27

$\boxed{27}$

84 - 57:

Step 1: Units place. Since $4 < 7$, borrow 1 from the tens place ($8$ becomes $7$). Now units: $14 - 7 = 7$.

Step 2: Tens place. $7 - 5 = 2$.

84 - 57 = 27

$\boxed{27}$

92 - 38:

Step 1: Units place. Since $2 < 8$, borrow 1 from the tens place ($9$ becomes $8$). Now units: $12 - 8 = 4$.

Step 2: Tens place. $8 - 3 = 5$.

92 - 38 = 54

$\boxed{54}$

69 - 27:

Step 1: Units place. $9 - 7 = 2$.

Step 2: Tens place. $6 - 2 = 4$.

69 - 27 = 42

$\boxed{42}$

88 - 49:

Step 1: Units place. Since $8 < 9$, borrow 1 from the tens place ($8$ becomes $7$). Now units: $18 - 9 = 9$.

Step 2: Tens place. $7 - 4 = 3$.

88 - 49 = 39

$\boxed{39}$

75 - 30:

Step 1: Units place. $5 - 0 = 5$.

Step 2: Tens place. $7 - 3 = 4$.

75 - 30 = 45

$\boxed{45}$

97 - 58:

Step 1: Units place. Since $7 < 8$, borrow 1 from the tens place ($9$ becomes $8$). Now units: $17 - 8 = 9$.

Step 2: Tens place. $8 - 5 = 3$.

97 - 58 = 39

$\boxed{39}$

61 - 24:

Step 1: Units place. Since $1 < 4$, borrow 1 from the tens place ($6$ becomes $5$). Now units: $11 - 4 = 7$.

Step 2: Tens place. $5 - 2 = 3$.

61 - 24 = 37

$\boxed{37}$