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Use the information above to write down inequalities associated with the lines represented by f and h. The feasible region is the shaded area.

Mathematics

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Question 1.1

1.1.1 Use the information above to write down inequalities associated with the lines represented by ff and hh.
The feasible region is the shaded area.

  • Line ff passes through points (0,45)(0, 45) and (40,5)(40, 5).
  1. Find the slope (mm) of line ff.

    m=y2−y1x2−x1=5−4540−0=−4040=−1m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 45}{40 - 0} = \frac{-40}{40} = -1
  2. Use the point-slope form y−y1=m(x−x1)y - y_1 = m(x - x_1) with point (0,45)(0, 45).

    y−45=−1(x−0)y - 45 = -1(x - 0) y−45=−xy - 45 = -x y=−x+45y = -x + 45 x+y=45x + y = 45

    Since the feasible region is below or on line ff, the inequality is x+y≤45x+y \le 45.

    • Line hh is a horizontal line passing through point B and C. From point C (20,25)(20, 25), we know y=25y=25. From point B, the y-coordinate is also 25. The line hh is y=25y=25. The feasible region is below or on line hh, so the inequality is y≤25y \le 25. However, the problem states "Given is the constraint 5≤y≤255 \le y \le 25". This means y≥5y \ge 5 and y≤25y \le 25. Line hh is y=25y=25. The feasible region is below or on this line. So, y≤25y \le 25. The line gg is y=5y=5. The feasible region is above or on this line. So, y≥5y \ge 5.

    The question asks for inequalities associated with lines ff and hh.
    The inequality for line ff is x+y≤45\boxed{x+y \le 45}.
    The inequality for line hh is y≤25\boxed{y \le 25}.

    **1.1.2

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